How to select nth element of the same type

Question

I would like to select the nth td from all of the td, how do I do that?

I know I can do it with document.querySelectorAll(\"td\")[nth

Answer 1

var result = document.querySelectorAll("table td:nth-of-type(2)");

console.log(result);

<table>
  <tr><td>nope</td><td>nope</td></tr>
  <tr><td>nope</td><td>here</td></tr>
  
</table>  

UP. Snippet shows that you cannot select TD elements globally, but you can get nth td element in given TR. Is this what you are looking for?

there is selector :nth-of-type(77)

should help you.

nth-child selector counts all children of given element - including other types of tags. Also css selector counts from 1, when JS querySelector result array from 0

Answer 2

There is a pure css way named ==> :nth-of-type
For example to select the 77th td element of each parent in the document the syntax is

td:nth-of-type(77)

For more information about the :nth-of-type selector see the Morzilla developer network if these links will break let me know in a comment below.

//For the element it self see //
https://developer.mozilla.org/nl/docs/Web/CSS/:nth-of-type

//For syntax about all the selections you can make with :nth-child and :nth-of-type see // https://developer.mozilla.org/en-US/docs/Web/CSS/:nth-child

Answer 3

I know I can do it with document.querySelectorAll("td")[nth], but I'm looking for a pure css way.

There is no pure CSS equivalent. See Matching the first/nth element of a certain type in the entire document