Group by month in SQLite

Question

I have an SQLite database which contains transactions, each of them having a price and a transDate.

I want to retrieve the sum of the transactions

Answer 1

This another form:

SELECT SUM(price) AS price,
STRFTIME('%Y-%m-01', created_at) as created_at
FROM records
GROUP BY STRFTIME('%Y-%m-01', created_at);

Answer 2

SELECT
    SUM(Price) as Price, strftime('%m', myDateCol) as Month
FROM
    myTable
GROUP BY
    strftime('%m', myDateCol)

Answer 3

it is always good while you group by MONTH it should check YEAR also

select SUM(transaction) as Price, 
       DATE_FORMAT(transDate, "%m-%Y") as 'month-year' 
       from transaction group by DATE_FORMAT(transDate, "%m-%Y");

FOR SQLITE

select SUM(transaction) as Price, 
       strftime("%m-%Y", transDate) as 'month-year' 
       from transaction group by strftime("%m-%Y", transDate);

Answer 4

In Sqlite, if you are storing your date in unixepoch format, in seconds:

select count(myDate) as totalCount, 
strftime('%Y-%m', myDate, 'unixepoch', 'localtime') as yearMonth
from myTable group by strftime('%Y-%m', myDate, 'unixepoch', 'localtime');

If you are storing the date in unixepoch format, in milliseconds, divide by 1000:

select count(myDate/1000) as totalCount, 
strftime('%Y-%m, myDate/1000, 'unixepoch', 'localtime') as yearMonth
from myTable group by strftime('%Y-%m, myDate/1000, 'unixepoch', 'localtime');

Answer 5

Try the following:

SELECT SUM(price), strftime('%m', transDate) as month
FROM your_table
GROUP BY strftime('%m', transDate);

Use the corresponding page in SQLite documentation for future references.

Answer 6

You can group on the start of the month:

select  date(DateColumn, 'start of month')
,       sum(TransactionValueColumn)
from    YourTable
group by 
        date(DateColumn, 'start of month')