subtract 1 hour from date in unix shell script

Question

I have the following in a shell script. How can I subtract one hour while retaining the formatting?

DATE=`date \"+%m/%d/%Y -%H:%M:%S\"`

Answer 1

Convert to timestamp (a long integer), subtract the right number of milliseconds, reformat to the format you need.

Hard to give more details since you don't specify a programming language...

Answer 2

The following command works on recent versions of GNU date:

date -d '1 hour ago' "+%m/%d/%Y -%H:%M:%S"

Answer 3

Here another way to subtract 1 hour.

yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'` 
echo $yesterdayDate

Output:
2018-11-23 23:09

I hope that It can help someone. Best Regards!

Answer 4

$ date +%Y-%m-%d-%H 
2019-04-09-20

$ date -v-1H +%Y-%m-%d-%H 
2019-04-09-19

But in shell use as like date +%Y-%m-%d-%H, date -v-1H +%Y-%m-%d-%H

Answer 5

if you need substract with timestamp :

timestamp=$(date +%s -d '1 hour ago');

Answer 6

This work on my Ubuntu 16.04 date: date --date="@$(($(date +%s) - 3600))" "+%m/%d/%Y -%H:%M:%S" And the date version is date (GNU coreutils) 8.25