Why would Javascript `if…else if` not end with an `else`?

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误落风尘
误落风尘 2020-12-16 02:23

Here is a snippet of JavaScript code from a tutorial I was working with. I don’t understand why it doesn’t end with a final else clause; I thought that was a ru

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  • 2020-12-16 03:10

    Consider 3 Scenario
    Scenario 1: Boolean condition

    if (condition) {}
    else {}
    

    Specifying a condition as else if would be redundant, and it's really obvious to the reader what the code does. There is no argument for using else if in this case.

    Scenario 2: Infinite states

    Here we are interested in testing for conditions A and B (and so on), and we may or may not be interested in what happens if none of them holds:

    if (conditionA) {}
    else if (conditionB) {}
    else {} // this might be missing as it is in your case
    

    The important point here is that there isn't a finite number of mutually-exclusive states, for example: conditionA might be num % 2 == 0 and conditionB might be num % 3 == 0.

    I think it's natural and desirable to use a reasonable amount of branches here; if the branches become too many this might be an indication that some judicious use of OO design would result in great maintainability improvements.

    Scenario 3: Finite states

    This is the middle ground between the first two cases: the number of states is finite but more than two. Testing for the values of an enum-like type is the archetypal example:

    if (var == CONSTANT_FOO) {}
    else if (var == CONSTANT_BAR) {} // either this,
    else {} // or this might be missing
    

    In such cases using a switch is probably better because it immediately communicates to the reader that the number of states is finite and gives a strong hint as to where a list of all possible states might be found (in this example, constants starting with CONSTANT_). My personal criteria is the number of states I 'm testing against: if it's only one (no else if) I 'll use an if; otherwise, a switch. In any case, I won't write an else if in this scenario.

    Adding else as an empty catch-errors block

    This is directly related to scenario #2 above. Unless the possible states are finite and known at compile time, you can't say that "in any other case" means that an error occurred. Seeing as in scenario #2 a switch would feel more natural, I feel that using else this way has a bad code smell.

    Use a switch with a default branch instead. It will communicate your intent much more clearly:

    switch(direction) {
        case 'up': break;
        case 'down': break;
        default: // put error handling here if you want
    }
    

    This might be a bit more verbose, but it's clear to the reader how the code is expected to function. In my opinion, an empty else block would look unnatural and puzzling here.

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  • 2020-12-16 03:12

    Not having an else clause is fine syntactically. MDN Documentation Basically the second if becomes the body of the else, see the section on "how it would look like if the nesting were properly indented".

    As to whether it's bad practice I think that depends on intent. By not explicitly defining the final else clause, you might end up with a bug where a condition you didn't cover comes through. Consider this:

    if(myVariable > 0) {
       doSomething();
    } else if(myVariable < 0) {
       doSomethingElse();
    }
    

    Nothing happens if myVariable is 0. It would be hard to see if you were just glancing through the code. I would say if you run into this pattern it would be a code smell, something might be wrong, but it could be fine.

    The same logic could always be expressed with nested if statements. I would go with whatever is more readable.

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