SQL Server Management Studio - Finding all non empty tables

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隐瞒了意图╮ 2020-12-16 02:00

Is there a way for SQL Server Management Studio Express How to list all the non empty tables? I have over 100 tables to go through and check for data.

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6条回答
  • 2020-12-16 02:11

    Try :

    WITH TableRows AS
    (
       SELECT 
          SUM(row_count) AS [RowCount], 
          OBJECT_NAME(OBJECT_ID) AS TableName
       FROM 
          sys.dm_db_partition_stats
       WHERE 
          index_id = 0 OR index_id = 1
       GROUP BY 
          OBJECT_ID
    )
    
    SELECT *
    FROM TableRows
    WHERE [RowCount] > 0
    
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  • 2020-12-16 02:12

    Morris Miao's solution uses the deprecated sys.sysindexes view; and performs the join to INFORMATION_SCHEMA.TABLES on the basis of table name, which is not guaranteed to be unique; even within a database.

    Simon's solution is not scoped to the current database; but can be refined through the use of sys.tables:

    SELECT r.table_name, r.row_count, r.[object_id]
    FROM sys.tables t
    INNER JOIN (
        SELECT OBJECT_NAME(s.[object_id]) table_name, SUM(s.row_count) row_count, s.[object_id]
        FROM sys.dm_db_partition_stats s
        WHERE s.index_id in (0,1)
        GROUP BY s.[object_id]
    ) r on t.[object_id] = r.[object_id]
    WHERE r.row_count > 0
    ORDER BY r.table_name;
    
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  • 2020-12-16 02:14

    Lets say Tables can be of two types.

    1. Clustered Table ( Tables having a Clustered Index )
    2. Heap Tables ( Tables not having a Clustered Index )

    All tables in SQL Server are divided into partitions. So that all table will have atleast one partition .

    In sys.partitions, there exists one row for each partition of all tables.

    These rows in sys.partitions contains information about number of rows in that partition of the corresponding table.

    Since all tables in SQL Server contain aleast one partition, we can get the information about number of rows in a table from sys.partitions.

    SELECT
            OBJECT_NAME(T.OBJECT_ID) AS TABLE_NAME,
            SUM(P.ROWS)  AS TOTAL_ROWS
    FROM
            SYS.TABLES T
    INNER JOIN 
            SYS.PARTITIONS P 
            ON T.OBJECT_ID = P.OBJECT_ID
    WHERE 
            P.INDEX_ID IN (0,1)
    GROUP BY 
            T.OBJECT_ID
    HAVING 
            SUM(P.ROWS) > 0
    

    While taking sum of rows in different partitions, we are considering index_id (0,1)

    • index_id = 0 for Heap
    • index_id = 1 for Clustered index
    • index_id > 1 are for nonclustered index.

    A table can have either one clustered index or none.

    But that is not the case with nonclustered index. A table can have multiple nonclustered indexes. So we cannot use those index_id while summing rows.

    • Heap Tables will be having index_id = 0
    • Clustered Tables will be having index_id = 1
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  • 2020-12-16 02:26

    One could also use "Object Explorer Details (F7)", navigate to the "Tables"-Folder of the database of interest and set the Object Explorer Details to show thw Row Count (right click on the headers)

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  • 2020-12-16 02:30

    You could try using sysindexes and INFORMATION_SCHEMA.TABLES:)

    SELECT 'Table Name'=convert(char(25),t.TABLE_NAME),
          'Total Record Count'=max(i.rows)
    FROM sysindexes i, INFORMATION_SCHEMA.TABLES t
    WHERE t.TABLE_NAME = object_name(i.id)
          and t.TABLE_TYPE = 'BASE TABLE'
    GROUP BY t.TABLE_SCHEMA, t.TABLE_NAME
    HAVING max(i.rows)<=0
    
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  • 2020-12-16 02:33

    This is a slight improvement to @jophab's answer. It will show schema for tables as well as compare rows = 0 using sys.partitions.

    SELECT 
        sch.name as SchemaName,
        t.NAME AS TableName,
        p.rows AS RowCounts
    FROM 
        sys.tables t
    INNER JOIN 
        sys.partitions p ON t.object_id = p.OBJECT_ID 
    INNER JOIN sys.schemas sch
        on t.schema_id = sch.schema_id
    WHERE 
        t.NAME NOT LIKE 'dt%' 
        AND t.is_ms_shipped = 0
        AND p.rows = 0
    GROUP BY 
        sch.name,t.Name, p.Rows
    ORDER BY 
        sch.name,t.Name
    
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