Truncate a float and a double in java

Question

I want to truncate a float and a double value in java.

Following are my requirements: 1. if i have 12.49688f, it should be printed as 12.49 without rounding off 2

Answer 1

double d = <some-value>;
System.out.println(String.format("%.2f", d - 0.005);

Answer 2

I have the same problem using Android, you can use instead:

DecimalFormat df = new DecimalFormat("##.##");
df.setRoundingMode(RoundingMode.DOWN);

but for this API Level 9 is required.

Another fast solution is:

double number = 12.43543542;
int aux = (int)(number*100);//1243
double result = aux/100d;//12.43

Answer 3

try this out-

DecimalFormat df = new DecimalFormat("##.##");
df.setRoundingMode(RoundingMode.DOWN);
System.out.println(df.format(12.49688f));
System.out.println(df.format(12.456));
System.out.println(df.format(12.0));

Here, we are using decimal formatter for formating. The roundmode is set to DOWN, so that it will not auto-round the decimal place.

The expected result is:

12.49
12.45
12

Answer 4

Try using DecimalFormat and set the RoundingMode to match what you need.

Answer 5

take a look with DecimalFormat() :

DecimalFormat df = new DecimalFormat("#.##");
DecimalFormatSymbols dfs = new DecimalFormatSymbols();
dfs.setDecimalSeparator(',');
df.setDecimalFormatSymbols(dfs);

Answer 6

Check java.math.BigDecimal.round(MathContext).