How to find maximum avg

Question

I am trying to display the maximum average salary; however, I can\'t seem to get it to work.

I can get a list of the average salaries to display with:

Answer 1

Here is how to also get the worker_id, inspired by previous answers:

SELECT worker_id, MAX(avg_salary)
FROM (SELECT worker_id, AVG(salary) AS avg_salary
      FROM workers
      GROUP BY worker_id);

Answer 2

You can in this way that the first row is sorted in descending based on average find

select top 1  worker_id, avg(salary) as avgsalary 
      from workers
      group by worker_id 
      order by avgsalary desc

Answer 3

You can fix the query by adding a column alias to the column within the sub-query, like so:

select max(avg_salary)
from (select worker_id, avg(salary) avg_salary
      from workers
      group by worker_id);

However, if worker_id uniquely identifies records on the workers table, this is functionally equivalent to (can be simplified to):

select max(salary) from workers;