How to find maximum avg

Question

I am trying to display the maximum average salary; however, I can\'t seem to get it to work.

I can get a list of the average salaries to display with:

Answer 1

select worker_id, avgsal 
from 
(
  select worker_id, avg(salary) as avgsal 
  from workers 
  group by worker_id
) 
where avgsal=(select  max(avgsal) 
              from (select worker_id, avg(salary) as avgsal 
                    from workers group by worker_id))

This will display the highest average along with worker id

Answer 2

select worker_id, avg(salary)
from workers
group by worker_id
having avg(salary) = (select max(avgsal) from 
(select worker_id, avg(salary) as avgsal 
from workers 
group by worker_id));

This should also work i guess

Answer 3

As explained here you can use

SELECT worker_id, AVG(salary)
FROM workers
GROUP BY worker_id
HAVING AVG(salary) = (SELECT MAX(AVG(salary)) FROM workers GROUP BY worker_id) 

Answer 4

https://stackoverflow.com/a/8050885/12190487 shows the folllowing error

ER_DERIVED_MUST_HAVE_ALIAS: Every derived table must have its own alias

Use alias for the new formed column you are selecting from

select max(avg_salary)
from (select worker_id, avg(salary) AS avg_salary
      from workers
      group by worker_id) as avg ; 

Answer 5

You can also do this with a single select statement (combining both max and avg) like this

select max(avg(salary)) max_avg_salary
from workers
group by worker_id;

Answer 6

Columns resulting from aggregate functions (e.g. avg) usually get arbitrary names. Just use an alias for it, and select on that:

select max(avg_salary)
from (select worker_id, avg(salary) AS avg_salary
      from workers
      group by worker_id) As maxSalary;