MySQL Second (or third) Index Of in String

Question

What would be the simplest way to locate the index of the third space in a string.

My goal is to get CCC out of this space separated list: AAAA BB

Answer 1

use below query to find any random id from table after group by. Here id is the autoincrement_id.

SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(id),",",FLOOR(RAND()*COUNT(DISTINCT id))+1),",",-1) AS random_id FROM tableName GROUP BY groupbyColumn

Answer 2

DROP FUNCTION IF EXISTS `Find_string_by_position`$$

CREATE DEFINER=`root`@`localhost` FUNCTION
`Find_string_by_position`(str VARCHAR(255), delimeter VARCHAR(255),pos INT(2)) RETURNS VARCHAR(255) CHARSET utf8mb4 BEGIN
       DECLARE s VARCHAR(255);  
       DECLARE d VARCHAR(255); 
       DECLARE p INT DEFAULT 1;
       DECLARE val VARCHAR(255);


       SET s = LCASE(str); 
       SET d = delimeter;
       SET p = pos;
       SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(s,d,p),d,-1) INTO @val; 

       RETURN @val;  

   END$$

DELIMITER ;

Answer 3

You could use SUBSTRING_INDEX.

Answer 4

Generally you can select the nth word in a string using:

SET @N = 3; -- 3rd word
SET @delimiter = ' ';
SELECT
  SUBSTRING_INDEX(SUBSTRING_INDEX(words, @delimiter, @N), @delimiter, -1)
FROM
  my_table

Answer 5

You would want to use SUBSTRING_INDEX function like this

SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(field, ' ', 3), ' ', -1)
FROM table

The inner function call would get you to AAAA BBBB CCCC while the outer function call would pare that down to just CCCC.