In sequelize it\'s possible to create a row and all it\'s association in one go like this:
return Product.create({
title: \'Chair\',
User: {
first_na
First you have to find model including sub model which you want to update. then you can get reference of sub model to update easily. i am posting an example for your reference. hope it will help.
var updateProfile = { name: "name here" };
var filter = {
where: {
id: parseInt(req.body.id)
},
include: [
{ model: Profile }
]
};
Product.findOne(filter).then(function (product) {
if (product) {
return product.Profile.updateAttributes(updateProfile).then(function (result) {
return result;
});
} else {
throw new Error("no such product type id exist to update");
}
});
If you want to update both models(Product & Profile) at once. One of the approaches can be:
// this is an example of object that can be used for update
let productToUpdate = {
amount: 'new product amount'
Profile: {
name: 'new profile name'
}
};
Product
.findById(productId)
.then((product) => {
if(!product) {
throw new Error(`Product with id ${productId} not found`);
}
product.Profile.set(productToUpdate.Profile, null);
delete productToUpdate.Profile; // We have to delete this object to not reassign values
product.set(productToUpdate);
return sequelize
.transaction((t) => {
return product
.save({transaction: t})
.then((updatedProduct) => updatedProduct.Profile.save());
})
})
.then(() => console.log(`Product & Profile updated!`))
await Job.update(req.body, {
where: {
id: jobid
}
}).then(async function () {
await Job.findByPk(jobid).then(async function (job) {
await Position.findOrCreate({ where: { jobinput: req.body.jobinput } }).then(position => {
job.setPositions(position.id)
})
})
Here positon belongsToMany job