PHP: How to get Sunday and Saturday given a date input?

Question

How can I get the Sunday and Saturday of the week given a specific date?

For example:

input: Monday, September 28, 2009

output should be:

Answer 1

You may find my Date Time Helper much handy in this case , it can finish in 3 Lines

http://normandqq.github.io/Date-Time-Helper/

    $date = '2013-08-11';
    $monday = Model_DTHpr::getMondayByDate($date);
    $sunday = Model_DTHpr::adjustDays("add",$monday,6);

Out Put:

    2013-08-05 //Monday
    2013-08-11 //Sunday

Answer 2

Get Sunday Php Code:

echo "Today Is : " . date("d-m-Y"); 
$dw = date( "w");
$dw = 7-$dw;
echo "\nNext Sunday Is" .date('d-m-Y', strtotime("+$dw days")); 

Answer 3

take a look at strtotime

i.e.

strtotime('next sunday', strtotime($your_date_string));

Answer 4

the issue with the 'correct' answer is, what if the supplied date is Sunday? Then it will give you the previous Sunday, instead of the current Sunday. Same issue with Saturday.

$s = 'Monday, September 28, 2009';
$time = strtotime($s);
if(date('D', $time) == "Sun"){
    $start = strtotime(' 12pm', $time);
}
else {
    $start = strtotime('last sunday, 12pm', $time);
}
if(date('D', $time) == "Sat"){
    $start = strtotime(' 12pm', $time);
}
else {
    $start = strtotime('next saturday, 12pm', $time);
}
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";