Group by hour in SQLAlchemy?

Question

How do I group query results by the hour part of a datetime column in SQLAlchemy?

Answer 1

If I remember correctly you must first extract the hour from your timestamp and then you can group by that.

query(extract('hour', timeStamp).label('h')).group_by('h')

Answer 2

This works for PostgreSQL:

.group_by(func.date_trunc('hour', date_col))

Answer 3

You can also do it in Python. Assuming you have an ordered query_result :

from itertools import groupby

def grouper( item ): 
    return item.created.hour
for ( hour, items ) in groupby( query_result, grouper ):
    for item in items:
        # do stuff

This answer is adapted from an answer to a similar question here

Answer 4

Recently I had to do a similar thing using SqlAlchemy and MySQL and ended up using the DATE_FORMAT (http://www.w3schools.com/sql/func_date_format.asp) to group by hour, minute, second

.group_by(func.date_format(date_col, '%H:%i:%s'))

To only group by hour it would be '%H' instead of '%H:%I:%s'

Answer 5

In Oracle, use func.trunc(MyTable.dt, 'HH')

It is a bit finicky, however. This fails:

q = session.query(func.trunc(MyTable.dt, 'HH'), func.sum(MyTable.qty) \
           .group_by(func.trunc(MyTable.dt, 'HH'))

But this succeeds:

trunc_date = func.trunc(MyTable.dt, 'HH')
q = session.query(trunc_date, func.sum(MyTable.qty) \
           .group_by(trunc_date)

Thanks to this thread for the tip.