In order to replace the default Spring security login form I came up with this solution:
The best solution for me is to use the default <button>
tag instead. Since typical button styling is not being applied (in my case I am using Primefaces), I set it manually. Here's the whole result:
<h:outputStylesheet library="primefaces" name="jquery/ui/jquery-ui.css" />
<h:outputStylesheet library="css" name="login.css" />
<div class="message">
<c:if test="#{param.error == 1 and SPRING_SECURITY_LAST_EXCEPTION != null}">
<span class="error">#{SPRING_SECURITY_LAST_EXCEPTION.message}</span>
</c:if>
</div>
<div class="login">
<form action="../j_spring_security_check" method="post">
<h:panelGrid columns="2">
<h:outputText value="Username" />
<h:inputText id="j_username" />
<h:outputText value="Password" />
<h:inputSecret id="j_password" />
</h:panelGrid>
<div class="submit">
<button type="submit" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-text-only">
<span class="ui-button-text">Login</span>
</button>
</div>
</form>
</div>
Your action attribute should be an EL expression like follows:
action="#{managedBean.method}"
Your best chance is to use the onclick property of the button. This is an example with a primefaces commandButton, but it will also work for jsf components because it uses the (native) javascript onclick function.
<h:form>
<p:commandButton value="Submit" onclick="alert('JS!')" actionListener="#{tweetBean.addTweet()}" update=":tabView,:trends,:tweetsnr" />
</h:form>
<h:form id="login" prependId="false" onsubmit="document.getElementById('login').action='j_security_check';">