Is there any convenient way to populate a table with all dates in a given range in Google BigQuery? What I need are all dates from 2015-06-01 till CURRENT_DATE(), so somethi
Mikhail's answer works for BigQuery's legacy sql syntax perfectly. This solution is a slightly easier one if you're using the standard SQL syntax.
BigQuery standard SQL syntax actually has a built in function, GENERATE_DATE_ARRAY for creating an array from a date range. It takes a start date, end date and INTERVAL
. For example:
SELECT day
FROM UNNEST(
GENERATE_DATE_ARRAY(DATE('2015-06-01'), CURRENT_DATE(), INTERVAL 1 DAY)
) AS day
If you wanted the week and year you could use
SELECT EXTRACT(YEAR FROM day), EXTRACT(WEEK FROM day)
FROM UNNEST(
GENERATE_DATE_ARRAY(DATE('2015-06-01'), CURRENT_DATE(), INTERVAL 1 WEEK)
) AS day
all dates from 2015-06-01 till CURRENT_DATE()
SELECT DATE(DATE_ADD(TIMESTAMP("2015-06-01"), pos - 1, "DAY")) AS DAY
FROM (
SELECT ROW_NUMBER() OVER() AS pos, *
FROM (FLATTEN((
SELECT SPLIT(RPAD('', 1 + DATEDIFF(TIMESTAMP(CURRENT_DATE()), TIMESTAMP("2015-06-01")), '.'),'') AS h
FROM (SELECT NULL)),h
)))
all weeks between the two dates
SELECT YEAR(DAY) AS y, WEEK(DAY) AS w
FROM (
SELECT DATE(DATE_ADD(TIMESTAMP("2015-06-01"), pos - 1, "DAY")) AS DAY
FROM (
SELECT ROW_NUMBER() OVER() AS pos, *
FROM (FLATTEN((
SELECT SPLIT(RPAD('', 1 + DATEDIFF(TIMESTAMP(CURRENT_DATE()), TIMESTAMP("2015-06-01")), '.'),'') AS h
FROM (SELECT NULL)),h
)))
)
GROUP BY y, w