I have a Ruby DateTime which gets filled from a form. Additionally I have n hours from the form as well. I\'d like to subtract those n hours from the previous DateTime. (To
If I'm allowed to use Time
instead of DateTime
(There are several ways to translate one to another):
# Just remove the number of seconds from the Time object
Time.now - (6 * 60 * 60) # 6 hours ago
The advance method is nice if you want to be more explicit about behavior like this.
adjusted = time_from_form.advance(:hours => -n)
You just need to take off fractions of a day.
two_hours_ago = DateTime.now - (2.0/24)
You can just subtract less than one whole day:
two_hours_ago = DateTime.now - (2/24.0)
This works for minutes and anything else too:
hours = 10
minutes = 5
seconds = 64
hours = DateTime.now - (hours/24.0) #<DateTime: 2015-03-11T07:27:17+02:00 ((2457093j,19637s,608393383n),+7200s,2299161j)>
minutes = DateTime.now - (minutes/1440.0) #<DateTime: 2015-03-11T17:22:17+02:00 ((2457093j,55337s,614303598n),+7200s,2299161j)>
seconds = DateTime.now - (seconds/86400.0) #<DateTime: 2015-03-11T17:26:14+02:00 ((2457093j,55574s,785701811n),+7200s,2299161j)>
If floating point arithmetic inaccuracies are a problem, you can use Rational
or some other safe arithmetic utility.
You could do this.
adjusted_datetime = (datetime_from_form.to_time - n.hours).to_datetime
n/24.0
trick won't work properly as floats are eventually rounded:
>> DateTime.parse('2009-06-04 02:00:00').step(DateTime.parse('2009-06-04 05:00:00'),1.0/24){|d| puts d}
2009-06-04T02:00:00+00:00
2009-06-04T03:00:00+00:00
2009-06-04T03:59:59+00:00
2009-06-04T04:59:59+00:00
You can, however, use Rational class instead:
>> DateTime.parse('2009-06-04 02:00:00').step(DateTime.parse('2009-06-04 05:00:00'),Rational(1,24)){|d| puts d}
2009-06-04T02:00:00+00:00
2009-06-04T03:00:00+00:00
2009-06-04T04:00:00+00:00
2009-06-04T05:00:00+00:00