partition string in python and get value of last segment after colon

Question

I need to get the value after the last colon in this example 1234567

client:user:username:type:1234567

I don\'t need anything else from the

Answer 1

Use this:

"client:user:username:type:1234567".split(":")[-1]

Answer 2

You could also use pygrok.

from pygrok import Grok
text = "client:user:username:type:1234567"
pattern = """%{BASE10NUM:type}"""
grok = Grok(pattern)
print(grok.match(text))

returns

{'type': '1234567'}

Answer 3

result = mystring.rpartition(':')[2]

If you string does not have any :, the result will contain the original string.

An alternative that is supposed to be a little bit slower is:

result = mystring.split(':')[-1]

Answer 4

foo = "client:user:username:type:1234567"
last = foo.split(':')[-1]