Get the inner HTML of a element in lxml

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I am trying to get the HTML content of child node with lxml and xpath in Python. As shown in code below, I want to find the html content of the each of product nodes. Does i

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南笙

2020-12-13 19:21

You can use product.text_content()

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谎友^

2020-12-13 19:23
another way to do this
```
x=doc.xpath("//div[@class='name']/parent::*")
print(map(etree.tostring,x))
```
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忘掉有多难

2020-12-13 19:27
```
from lxml import etree
print(etree.tostring(root, pretty_print=True))
```
you may see more examples here: http://lxml.de/tutorial.html
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甜味超标

2020-12-13 19:28

Simple function to get innerHTML or innerXML
.
Try it out directly https://pyfiddle.io/fiddle/631aa049-2785-4c58-bf82-eff4e2f8bedb/
.

function


def innerXML(elem):
    elemName = elem.xpath('name(/*)')
    resultStr = ''
    for e in elem.xpath('/'+ elemName + '/node()'):
        if(isinstance(e, str) ):
            resultStr = resultStr + ''
        else:
            resultStr = resultStr + etree.tostring(e, encoding='unicode')

    return resultStr

invocation

XMLElem = etree.fromstring("<div>I am<name>Jhon <last.name> Corner</last.name></name>.I work as <job>software engineer</job><end meta='bio' />.</div>")
print(innerXML(XMLElem))

.
Logic Behind

get the outermost element name first,
Then get all the child nodes
Convert all the child nodes to string using tostring
Concatinate Them

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走了就别回头了

2020-12-13 19:34

I believe you want to use the tostring() method:

from lxml import etree

tree = etree.fromstring('<html><head><title>foo</title></head><body><div class="name"><p>foo</p></div><div class="name"><ul><li>bar</li></ul></div></body></html>')
for elem in tree.xpath("//div[@class='name']"):
     # pretty_print ensures that it is nicely formatted.
     print etree.tostring(elem, pretty_print=True)

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有刺的猬

2020-12-13 19:37

After right clicking (copy, copy xpath) on the specific field you want (in chrome's inspector), you might get something like this:

//*[@id="specialID"]/div[12]/div[2]/h4/text()[1]

If you wanted that text element for each "specialID"

//*[@id="specialID"]/div/div[2]/h4/text()[1]

You could select another field and it'll interleave the results

//*[@id="specialID"]/div/div[2]/h4/text()[1] | //*[@id="specialID"]/div/some/weird/path[95]

Example could be improved, but it illustrates the point:

//*[@id="mw-content-text"]/div/ul[1]/li[11]/text()

from lxml import html
import requests
page = requests.get('https://en.wikipedia.org/wiki/Web_scraping')
tree = html.fromstring(page.content)
data = tree.xpath('//*[@id="mw-content-text"]/div/ul[1]/li/a/text() | //*[@id="mw-content-text"]/div/ul[1]/li/text()[1]')
print(len(data))
for i in range(len(data)):
    print(data[i])

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