how to extract numeric values from input string in java

Question

How can I extract only the numeric values from the input string?

For example, the input string may be like this:

String str=\"abc d 1234567890pqr 548         


        

Answer 1

Just extract the digits

String str=" abc d 1234567890pqr 54897";        

for(int i=0; i<str.length(); i++)
    if( str.charAt(i) > 47 && str.charAt(i) < 58)
        System.out.print(str.charAt(i));

Another version

String str=" abc d 1234567890pqr 54897";        
boolean flag = false;
for(int i=0; i<str.length(); i++)
    if( str.charAt(i) > 47 && str.charAt(i) < 58) {
        System.out.print(str.charAt(i));
        flag = true;
    } else {
        System.out.print( flag ? '\n' : "");
        flag = false;
    }

Answer 2

Example using java Scanner class

import java.util.Scanner;

Scanner s = new Scanner( "abc d 1234567890pqr 54897" );
s.useDelimiter( "\\D+" );
while ( s.hasNextInt() ){
    s.nextInt(); // get int
}

Answer 3

public class ExtractNum

{

  public static void main(String args[])

  {

   String input = "abc d 1234567890pqr 54897";

   String digits = input.replaceAll("[^0-9.]","");

   System.out.println("\nGiven Number is :"+digits);

  }

 }

Answer 4

 public static String convertBudgetStringToPriceInteger(String budget) {
    if (!AndroidUtils.isEmpty(budget) && !"0".equalsIgnoreCase(budget)) {
        double numbers = getNumericFromString(budget);
        if( budget.contains("Crore") ){
            numbers= numbers* 10000000;
        }else if(budget.contains("Lac")){
            numbers= numbers* 100000;
        }
        return removeTrailingZeroesFromDouble(numbers);
    }else{
        return "0";
    }
}

Get numeric value from alphanumeric string

 public static double getNumericFromString(String string){
    try {
        if(!AndroidUtils.isEmpty(string)){
            String commaRemovedString = string.replaceAll(",","");
            return Double.parseDouble(commaRemovedString.replaceAll("[A-z]+$", ""));
            /*return Double.parseDouble(string.replaceAll("[^[0-9]+[.[0-9]]*]", "").trim());*/

        }
    }catch (NumberFormatException e){
        e.printStackTrace();
    }
    return 0;
}

For eg . If i pass 1.5 lac or 15,0000 or 15 Crores then we can get numeric value from these fucntion . We can customize string according to our needs. For eg. Result would be 150000 in case of 1.5 Lac

Answer 5

String str = "abc d 1234567890pqr 54897";
str = str.replaceAll("[^\\d ]", "");

The result will be "1234567890 54897".

Answer 6

You can use str = str.replaceAll("replaced_string","replacing_string");

String str=" abc d 1234567890pqr 54897";
String str_rep1=" abc d ";
String str_rep2="pqr ";
String result1=str.replaceAll("", str_rep1);
String result2=str.replaceAll(",",str_rep2);

also what npinti suggests is fine to work with.