How to exclude one particular field from a collection in Mongoose?

Question

I have a NodeJS application with Mongoose ODM(Mongoose 3.3.1). I want to retrieve all fields except 1 from my collection.For Example: I have a collection Pr

Answer 1

You could do this

const products = await Product.find().select(['-image'])

Answer 2

I don't know where you read about that .exclude function, because I can't find it in any documentation.

But you can exclude fields by using the second parameter of the find method.

Here is an example from the official documentation:

db.inventory.find( { type: 'food' }, { type:0 } )

This operation returns all documents where the value of the type field is food, but does not include the type field in the output.

Answer 3

Use query.select for field selection in the current (3.x) Mongoose builds.

Prefix a field name you want to exclude with a -; so in your case:

Query.select('-Image');

Quick aside: in JavaScript, variables starting with a capital letter should be reserved for constructor functions. So consider renaming Query as query in your code.

Answer 4

Model.findOne({ _id: Your Id}, { password: 0, name: 0 }, function(err, user){
  // put your code
});

this code worked in my project. Thanks!! have a nice day.

Answer 5

I am use this with async await

async (req, res) => {
      try { 
        await User.findById(req.user,'name email',(err, user) => {
          if(err || !user){
            return res.status(404)
          } else {
            return res.status(200).json({
              user,
            });
          }
        });
      } catch (error) {
        console.log(error);
      }

Answer 6

In the updated version of Mongoose you can use it in this way as below to get selected fields.

user.findById({_id: req.body.id}, 'username phno address').then(response => {
  res.status(200).json({
    result: true,
    details: response
  });
}).catch(err => {
  res.status(500).json({ result: false });
});