How to split an Int to its individual digits?

Question

I am trying to split an Int into its individual digits, e.g. 3489 to 3 4 8 9, and then I want to put the digits in an Int array.

I have already tried putting the num

Answer 1

We can also extend the StringProtocol and create a computed property:

edit/update: Xcode 11.5 • Swift 5.2

extension StringProtocol  {
    var digits: [Int] { compactMap(\.wholeNumberValue) }
}

---

let string = "123456"
let digits = string.digits // [1, 2, 3, 4, 5, 6]

---

extension LosslessStringConvertible {
    var string: String { .init(self) }
}

extension Numeric where Self: LosslessStringConvertible {
    var digits: [Int] { string.digits }
}

---

let integer = 123
let integerDigits = integer.digits // [1, 2, 3]

let double = 12.34
let doubleDigits = double.digits   // // [1, 2, 3, 4]

---

In Swift 5 now we can use the new Character property wholeNumberValue

let string = "123456"

let digits = string.compactMap{ $0.wholeNumberValue } // [1, 2, 3, 4, 5, 6]

Answer 2

Swift 5

extension Int {
    func digits() -> [Int] {
        var digits: [Int] = []
        var num = self
        
        digits.append(num % 10)
        
        while num >= 10  {
            num = num / 10
            digits.append(num % 10)
        }
        
        return digits.reversed()
    }
}