PHP Count round thousand to a K style count like facebook Share . . . Twitter Button ect

Question

Ok so I am trying to turn my hit counter to round thousands to a single digit too display 3 thousand hits as 3K for example, like the Facebook Share and Twitter Tweet Button

Answer 1

Here comes a PHP function to format numbers to nearest thousands such as Kilos, Millions, Billions, and Trillions with comma

Function

function thousandsCurrencyFormat($num) {

  if($num>1000) {

        $x = round($num);
        $x_number_format = number_format($x);
        $x_array = explode(',', $x_number_format);
        $x_parts = array('k', 'm', 'b', 't');
        $x_count_parts = count($x_array) - 1;
        $x_display = $x;
        $x_display = $x_array[0] . ((int) $x_array[1][0] !== 0 ? '.' . $x_array[1][0] : '');
        $x_display .= $x_parts[$x_count_parts - 1];

        return $x_display;

  }

  return $num;
}

Output

thousandsCurrencyFormat(3000) - 3k
thousandsCurrencyFormat(35500) - 35.5k
thousandsCurrencyFormat(905000) - 905k
thousandsCurrencyFormat(5500000) - 5.5m
thousandsCurrencyFormat(88800000) - 88.8m
thousandsCurrencyFormat(745000000) - 745m
thousandsCurrencyFormat(2000000000) - 2b
thousandsCurrencyFormat(22200000000) - 22.2b
thousandsCurrencyFormat(1000000000000) - 1t (1 trillion)

Resources

https://code.recuweb.com/2018/php-format-numbers-to-nearest-thousands/

Answer 2

Question is 8 years old but each time I see an answer that contains an else statement, I think it can be done in a better (cleaner) way.

<?php

if (!function_exists('format_number_in_k_notation')) {
    function format_number_in_k_notation(int $number): string
    {
        $suffixByNumber = function () use ($number) {
            if ($number < 1000) {
                return sprintf('%d', $number);
            }

            if ($number < 1000000) {
                return sprintf('%d%s', floor($number / 1000), 'K+');
            }

            if ($number >= 1000000 && $number < 1000000000) {
                return sprintf('%d%s', floor($number / 1000000), 'M+');
            }

            if ($number >= 1000000000 && $number < 1000000000000) {
                return sprintf('%d%s', floor($number / 1000000000), 'B+');
            }

            return sprintf('%d%s', floor($number / 1000000000000), 'T+');
        };

        return $suffixByNumber();
    }
}

dump(format_number_in_k_notation(123)); // "123"
dump(format_number_in_k_notation(73000)); // "73K+"
dump(format_number_in_k_notation(216000)); // "216K+"
dump(format_number_in_k_notation(50400123)); // "50M+"
dump(format_number_in_k_notation(12213500100600)); // "12T+"

die;

Answer 3

Rounding up, not accounting for any abbreviations above 'k' or thousands, showing one decimal place.

function kConverter($number) {
    if ($number >= 1000) {
        return number_format(($number / 1000), 1) . 'k';
    } else {
        return $number;
    }
}

kConverter(1)          = 1
kConverter(111)        = 111
kConverter(999)        = 999
kConverter(1000)       = "1.0k"
kConverter(1499)       = "1.5k"
kConverter(1500)       = "1.5k"
kConverter(1501)       = "1.5k"
kConverter(1550)       = "1.6k"
kConverter(11501)      = "11.5k"
kConverter(1000000000) = "1,000,000.0k"
kConverter(1234567890) = "1,234,567.9k"

Answer 4

My func

function numsize($size,$round=2){
    $unit=['', 'K', 'M', 'B', 'T'];
    return round($size/pow(1000,($i=floor(log($size,1000)))),$round).$unit[$i];
}

Answer 5

This is a modified version with k and m lowercase and show one decimal place for milllions.

<?php

    if ($value > 999 && $value <= 999999) {
    $result  = floor($value / 1000) . 'k';
    } elseif ($value > 999999) {
    $result  = number_format((float)$value , 1, '.', '')/1000000 . 'm';
    } else {
    $result  = $value;
    }
?>

Answer 6

Use floor instead of round if you want 3500 to round down to 3 K.

Otherwise, your code works, albeit problematically. Try this:

if ($postresultscount > 1000) {
  $result = floor($postresultscount / 1000) . 'K';
} else {
  $result = $postresultscount;
}

echo 'document.write("' . $result . '")";

It also appears you're writing JavaScript using PHP—take care.