Get current quarter in year with javascript

Question

How can I get the current quarter we are in with javascript? I am trying to detect what quarter we are currently in, e.g. 2.

EDIT And how can I coun

Answer 1

if the first solution doesn't work than you can just adjust it to the range you would like

var today = new Date();
var month = now.getMonth();
var quarter;
if (month < 4)
  quarter = 1;
else if (month < 7)
  quarter = 2;
else if (month < 10)
  quarter = 3;
else if (month < 13)
  quarter = 4;

Answer 2

Assuming January through March are considered Q1 (some countries/companies separate their financial year from their calendar year), the following code should work:

var today = new Date();
var quarter = Math.floor((today.getMonth() + 3) / 3);

This gives you:

Month      getMonth()  quarter
---------  ----------  -------
January         0         1
February        1         1
March           2         1
April           3         2
May             4         2
June            5         2
July            6         3
August          7         3
September       8         3
October         9         4
November       10         4
December       11         4

As to how to get the days remaining in the quarter, it's basically figuring out the first day of the next quarter and working out the difference, something like:

var today = new Date();
var quarter = Math.floor((today.getMonth() + 3) / 3);
var nextq;
if (quarter == 4) {
    nextq = new Date (today.getFullYear() + 1, 1, 1);
} else {
    nextq = new Date (today.getFullYear(), quarter * 3, 1);
}
var millis1 = today.getTime();
var millis2 = nextq.getTime();
var daydiff = (millis2 - millis1) / 1000 / 60 / 60 / 24;

That's untested but the theory is sound. Basically create a date corresponding to the next quarter, convert it and today into milliseconds since the start of the epoch, then the difference is the number of milliseconds.

Divide that by the number of milliseconds in a day and you have the difference in days.

That gives you (at least roughly) number of days left in the quarter. You may need to fine-tune it to ensure all times are set to the same value (00:00:00) so that the difference is in exact days.

It may also be off by one, depending on your actual definition of "days left in the quarter".

But it should be a good starting point.

Answer 3

function getQuarter(d) {
  return Math.floor((d.getMonth()/3 % 4) + 1);
}

Answer 4

Depend on month

 var date = new Date();     
 var quarter =  parseInt(date.getMonth() / 3 ) + 1 ;

Depend on Date

 var date = new Date();    
 var firstday = new Date(date.getFullYear(),0,1); // XXXX/01/01
 var diff = Math.ceil((date - firstday) / 86400000); 
 // a quarter is about 365/4 
 quarter =  parseInt( diff / ( 365/ 4 )) + 1 
 // if today is 2012/01/01, the value of quarter  is  1.

Answer 5

// Set Period Function
  SetPeriod(SelectedVal) {
    try {
      if (SelectedVal === '0') { return; }
      if (SelectedVal != null) {
        let yrf: number, mtf: number, dyf: number, yrt: number, mtt: number, dyt: number, dtf: any, dtt: any;
        let dat = new Date();
        let q = 0;
        switch (SelectedVal) {
          case '-1': // Not specify
            frm = ''; to = '';
            return;
          case '0': // As specify
            break;
          case '1': // This Month
            yrf = yrt = dat.getUTCFullYear();
            mtf = mtt = dat.getUTCMonth();
            dyf = 1; dyt = this.getDaysInMonth(mtf, yrf);
            break;
          case '2': // Last Month
            dat.setDate(0); // 0 will result in the last day of the previous month
            dat.setDate(1); // 1 will result in the first day of the month
            yrf = yrt = dat.getUTCFullYear();
            mtf = mtt = dat.getUTCMonth();
            dyf = 1; dyt = this.getDaysInMonth(mtf, yrf);
            break;
          case '3': // This quater
            q = Math.ceil((dat.getUTCMonth()) / 3);
          // tslint:disable-next-line:no-switch-case-fall-through
          case '4': // Last quater
            if (q === 0) { q = Math.ceil(dat.getUTCMonth() / 3) - 1; if (q === 0) { q = 1; } }
            yrf = yrt = dat.getUTCFullYear();
            if (q === 1) {
              mtf = 0; mtt = 2;
              dyf = 1; dyt = 31;
            } else if (q === 2) {
              mtf = 3; mtt = 5;
              dyf = 1; dyt = 30;
            } else if (q === 3) {
              mtf = 6; mtt = 8;
              dyf = 1; dyt = 30;
            } else if (q === 4) {
              mtf = 9; mtt = 11;
              dyf = 1; dyt = 31;
            }
            break;
          case '6': // Last year
            dat = new Date(dat.getUTCFullYear(), 0, 1);
          // tslint:disable-next-line:no-switch-case-fall-through
          case '5': // This year
            yrf = yrt = dat.getUTCFullYear();
            mtf = 0; mtt = 11;
            dyf = 1; dyt = 31;
            break;
        }

        // Convert to new Date
        dtf = new Date(yrf, mtf, dyf);
        dtt = new Date(yrt, mtt, dyt);
        console.log('dtf', dtf);
        console.log('dtt', dtt);

      }
    } catch (e) {
      alert(e);
    }
  }



// Get Day in Month
  getDaysInMonth = (month: number, year: number) => {
    return new Date(year, month + 1, 0).getDate();
  }

Answer 6

It's not efficient or readable but it's in oneliner flavour.

(new Date(new Date().getFullYear(), Math.floor((new Date().getMonth() + 3) / 3) * 3, 1) - new Date()) / 86400000