SQL Server Group By Month

Question

I have a table which has this schema

ItemID    UserID    Year    IsPaid    PaymentDate  Amount
1         1         2009    0         2009-11-01  300
2                


        

Answer 1

Another approach, that doesn't involve adding columns to the result, is to simply zero-out the day component of the date, so 2016-07-13 and 2016-07-16 would both be 2016-07-01 - thus making them equal by month.

If you have a date (not a datetime) value, then you can zero it directly:

SELECT
    DATEADD( day, 1 - DATEPART( day, [Date] ), [Date] ),
    COUNT(*)
FROM
    [Table]
GROUP BY
    DATEADD( day, 1 - DATEPART( day, [Date] ), [Date] )

If you have datetime values, you'll need to use CONVERT to remove the time-of-day portion:

SELECT
    DATEADD( day, 1 - DATEPART( day, [Date] ),  CONVERT( date, [Date] ) ),
    COUNT(*)
FROM
    [Table]
GROUP BY
    DATEADD( day, 1 - DATEPART( day, [Date] ),  CONVERT( date, [Date] ) )