any() function in Python with a callback

Question

The Python standard library defines an any() function that

Return True if any element of the iterable is true. If the iterable is empty, return False.

Answer 1

You can use a combination of any and map if you really want to keep your lambda notation like so :

any(map(lambda e: isinstance(e, int) and e > 0, [1, 2, 'joe']))

But it is better to use a generator expression because it will not build the whole list twice.

Answer 2

How about:

>>> any(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
True

It also works with all() of course:

>>> all(isinstance(e, int) and e > 0 for e in [1,2,'joe'])
False