Count number of files with certain extension in Python

Question

I am fairly new to Python and I am trying to figure out the most efficient way to count the number of .TIF files in a particular sub-directory.

Doing some searching,

Answer 1

For this particular use case, if you don't want to recursively search in the subdirectory, you can use os.listdir:

len([f for f in os.listdir(myPath) 
     if f.endswith('.tif') and os.path.isfile(os.path.join(myPath, f))])

Answer 2

Your code is fine.

Yes, you're going to need to loop over those files to filter out the .tif files, but looping over a small in-memory array is negligible compared to the work of scanning the file directory to find these files in the first place, which you have to do anyway.

I wouldn't worry about optimizing this code.

Answer 3

If you do need to search recursively, or for some other reason don't want to use the glob module, you could use

file_count = sum(len(f for f in fs if f.lower().endswith('.tif')) for _, _, fs in os.walk(myPath))

This is the "Pythonic" way to adapt the example you found for your purposes. But it's not going to be significantly faster or more efficient than the loop you've been using; it's just a really compact syntax for more or less the same thing.

Answer 4

Something has to iterate over all files in the directory, and look at every single file name - whether that's your code or a library routine. So no matter what the specific solution, they will all have roughly the same cost.

If you think it's too much code, and if you don't actually need to search subdirectories recursively, you can use the glob module:

import glob
tifCounter = len(glob.glob1(myPath,"*.tif"))

Answer 5

try using fnmatch https://docs.python.org/2/library/fnmatch.html

import fnmatch,os
num_files = len(fnmatch.filter(os.listdir(your_dir),'*.tif'))
print(num_files)