How to construct a WebSocket URI relative to the page URI?

Question

I want to construct a WebSocket URI relative to the page URI at the browser side. Say, in my case convert HTTP URIs like

http://example.com:8000/path
https:/         


        

Answer 1

If your Web server has support for WebSockets (or a WebSocket handler module) then you can use the same host and port and just change the scheme like you are showing. There are many options for running a Web server and Websocket server/module together.

I would suggest that you look at the individual pieces of the window.location global and join them back together instead of doing blind string substitution.

var loc = window.location, new_uri;
if (loc.protocol === "https:") {
    new_uri = "wss:";
} else {
    new_uri = "ws:";
}
new_uri += "//" + loc.host;
new_uri += loc.pathname + "/to/ws";

Note that some web servers (i.e. Jetty based ones) currently use the path (rather than the upgrade header) to determine whether a specific request should be passed on to the WebSocket handler. So you may be limited in whether you can transform the path in the way you want.

Answer 2

Assuming your WebSocket server is listening on the same port as from which the page is being requested, I would suggest:

function createWebSocket(path) {
    var protocolPrefix = (window.location.protocol === 'https:') ? 'wss:' : 'ws:';
    return new WebSocket(protocolPrefix + '//' + location.host + path);
}

Then, for your case, call it as follows:

var socket = createWebSocket(location.pathname + '/to/ws');

Answer 3

Dead easy solution, ws and port, tested:

var ws = new WebSocket("ws://" + window.location.host + ":6666");

ws.onopen = function() { ws.send( .. etc

Answer 4

Here is my version which adds the tcp port in case it's not 80 or 443:

function url(s) {
    var l = window.location;
    return ((l.protocol === "https:") ? "wss://" : "ws://") + l.hostname + (((l.port != 80) && (l.port != 443)) ? ":" + l.port : "") + l.pathname + s;
}

Edit 1: Improved version as by suggestion of @kanaka :

function url(s) {
    var l = window.location;
    return ((l.protocol === "https:") ? "wss://" : "ws://") + l.host + l.pathname + s;
}

Edit 2: Nowadays I create the WebSocket this:

var s = new WebSocket(((window.location.protocol === "https:") ? "wss://" : "ws://") + window.location.host + "/ws");

Answer 5

On localhost you should consider context path.

function wsURL(path) {
    var protocol = (location.protocol === 'https:') ? 'wss://' : 'ws://';
    var url = protocol + location.host;
    if(location.hostname === 'localhost') {
        url += '/' + location.pathname.split('/')[1]; // add context path
    }
    return url + path;
}

Answer 6

easy:

location.href.replace(/^http/, 'ws') + '/to/ws'
// or if you hate regexp:
location.href.replace('http://', 'ws://').replace('https://', 'wss://') + '/to/ws'