Code Golf: Musical Notes

Answer 1

C 196 characters <<o>>

Borrowing a few ideas off strager. Interesting features include the n+++1 "triple +" operator and the <<o>> "evil eye" operator

#define P,putchar
N[99];*n=N;y;b;main(o){for(;scanf(" %c/%d",n,n+1)>0;n+=2);for(;y<11;)
n=*n?n:(y++P(10),N)P(b=y&1?32:45)P((o=10-(*n+++1)%7-y)?b:79)P(0<o&o<4&&*n?'|':b)
P(*n++<<o>>6&&0<o&o<4?92:b);}

Answer 2

C -- 293 characters

Still needs more compression, and it takes the args on the command line instead of reading them...

i,j,k,l;main(c,v)char **v;{char*t;l=4*(c-1)+2;t=malloc(10*l)+1;for(i=0;i<10;i
++){t[i*l-1]='\n';for(j=0;j<l;j++)t[i*l+j]=i&1?'-':' ';}t[10*l-1]=0;i=1;while
(--c){j='G'-**++v;if(j<3)j+=7;t[j*l+i++]='O';if(*++*v){t[--j*l+i]='|';t[--j*l
+i]='|';t[--j*l+i]='|';if(*++*v!='4'){t[j++*l+i+1]='\\';if(**v!='8'){t[j++*l+
i+1]='\\';if(**v!='1'){t[j++*l+i+1]='\\';}}}}i+=3;}puts(t);}

edit: fixed the E

edit: down to 293 characters, including the newlines...

#define X t[--j*l+i]='|'
#define Y t[j++*l+i+1]=92
i,j,k,l;main(c,v)char**v;{char*t;l=4*(c-1)+2;t=malloc(10*l)+1;for(i=10;i;)t[--i*
l-1]=10,memset(t+i*l,i&1?45:32,l-1);t[10*l-1]=0;for(i=1;--c;i+=3)j=71-**++v,j<3?
j+=7:0,t[j*l+i++]=79,*++*v?X,X,X,*++*v-52?Y,**v-56?Y,**v-49?Y:0:0:0:0;puts(t);}

Answer 3

LilyPond - 244 bytes

Technically speaking, this doesn't adhere to the output specification, as the output is a nicely engraved PDF rather than a poor ASCII text substitute, but I figured the problem was just crying out for a LilyPond solution. In fact, you can remove the "\autoBeamOff\cadenzaOn\stemUp" to make it look even more nicely formatted. You can also add "\midi{}" after the "\layout{}" to get a MIDI file to listen to.

o=#(open-file"o""w")p=#ly:string-substitute
#(format o"~(~a"(p"2'1""2"(p"4'1""4"(p"6'1""6"(p"8'1""8"(p"/""'"(p"C""c'"(p"D""d'"(p" ""/1"(p"
"" "(ly:gulp-file"M")))))))))))#(close-port o)\score{{\autoBeamOff\cadenzaOn\stemUp\include"o"}\layout{}}

Usage: lilypond thisfile.ly

Notes:

1. The input must be in a file named "M" in the same directory as the program.
2. The input file must end in a newline. (Or save 9 bytes by having it end in a space.)
3. The output is a PDF named "thisfile.pdf", where "thisfile.ly" is the name of the program.
4. I tested this with LilyPond 2.12.2; other versions might not work.

I haven't done much in LilyPond, so I'm not sure this is the best way to do this, since it has to convert the input to LilyPond format, write it to an auxiliary file, and then read it in. I currently can't get the built-in LilyPond parser/evaluator to work. :(

Now working on an ASCII-output solution.... :)

Answer 4

Ruby 136

n=gets;10.times{|y|puts (b=' -'[y&1,1])+n.split.map{|t|r=y-(5-t[0])%7
(r==3?'O':b)+(t[1]&&0<=r&&r<3?'|'<<(r<t[2,2].to_i/8?92:b):b+b)}*b}

Ruby 139 (Tweet)

n=gets;10.times{|y|puts (b=' -'[y&1,1])+n.split.map{|t|r=y-(5-t[0])%7
(r==3?'O':b)+(t[1]&&0<=r&&r<3?'|'<<(r<141>>(t[-1]&7)&3?92:b):b+b)}*b}

Ruby 143

n=gets.split;10.times{|y|puts (b=' -'[y&1,1])+n.map{|t|r=y-(5-t[0])%7;m=t[-1]
(r==3?'O':b)+(m<65&&0<=r&&r<3?'|'<<(r<141>>(m&7)&3?92:b):b+b)}*b}

Ruby 148

Here is another way to calculate the flags,
where m=ord(last character), #flags=1+m&3-(1&m/4)

and another way #flags=141>>(m&7)&3, that saves one more byte

n=gets.split;10.times{|y|b=' -'[y&1,1];n.each{|t|r=y-(5-t[0])%7;m=t[-1]
print b+(r==3?'O':b)+(m<65&&0<=r&&r<3?'|'<<(r<141>>(m&7)&3?92:b):b+b)}
puts}

Ruby 181

First try is a transliteration of my Python solution

n=gets.split;10.times{|y|r="";n.each{|x|o=y-(5-x[0])%7
r+=(b=" -"[y&1,1]+"O\\|")[0,1]+b[o==3?1:0,1]+b[-1<o&&o<3&&x[-1]<64?3:0,1]+b[-1<o&&o<(":862".index(x[-1]).to_i)?2:0,1]}
puts r}

Answer 5

C89 (186 characters)

#define P,putchar(
N[99];*n=N;y;e=45;main(q){for(;scanf(" %c/%d",n,n+1)>0;n
+=2);for(;y<11;q=y-(75-*n++)%7 P+q-4?e:79)P*n&&q<4&q>0?
124:e)P*n++/4>>q&&q?92:e))*n||(e^=13,n=N,y++P+10))P+e);}

Half-note support (+7 characters)

#define P,putchar(
N[99];*n=N;y;e=45;main(q){for(;scanf(" %c/%d",n,n+1)>0;n
+=2);for(;y<11;q=y-(75-*n++)%7 P+q-4?e:v<4?79:64)P*n&&q<4&q>0?
124:e)P*n++/4>>q&&q?92:e))*n||(e^=13,n=N,y++P+10))P+e);}

Answer 6

Lua, 307 Characters

b,s,o="\\",io.read("*l"),io.write for i=1,10 do for n,l in
s:gmatch("(%a)/?(%d*)")do x=n:byte() w=(x<69 and 72 or 79)-x
l=tonumber(l)or 1 d=i%2>0 and" "or"-"o(d..(i==w and"O"or
d)..(l>3 and i<w and i+4>w and"|"or d)..(l>7 and i==w-3
and b or l>15 and i==w-2 and b or l>31 and i==w-1 and b or
d))end o"\n"end