I am trying to create a simple lambda function, and I\'m running into an error.
My code is basically
console.log(\'Loading function\');
exports.han
Lets take a folder named 'sample' as an example which we want to zip. Lets assume there are some subfolders or files within the sample folder.
Q. What you have to do?
Ans - Following are the steps:
Q.What not to do?
Ans - Do not zip 'sample' folder. It won't work.
Grunt
Complete AWS Lambda Seed project is available on Git.
Step 1: Init npm module
npm init
Step 2: Install Grunt
npm install --save-dev grunt grunt-cli
Step 3: Install grunt-aws-lambda
npm install --save-dev grunt-aws-lambda
Step 4: Create Folder for Lambda service
# Create directory
mkdir lambdaTest
# Jump into folder
cd lambdaTest
# Create service file
touch lambdaTest.js
# Initialize npm
npm init
Keep your logic/code into lambdaTest.js
'use strict'
exports.handler = (event, context, callback) => {
console.log("Hello it's looks like working");
};
Step 5: Create Gruntfile.js
Navigate back to root folder
touch Gruntfile.js
'use strict'
module.exports = function (grunt) {
grunt.initConfig({
lambda_invoke: {
lambdaTest: {
options: {
file_name: "lambdaTest/lambdaTest.js",
event: "lambdaTest/test.json",
}
}
},
lambda_package: {
lambdaTest: {
options: {
package_folder: 'lambdaTest/'
}
}
},
lambda_deploy: {
lambdaTest: {
arn: 'arn:aws:lambda:eu-central-1:XXXXXXXX:function:lambdaTest',
options: {
credentialsJSON: 'awsCredentials.json',
region: "eu-central-1"
},
}
},
});
grunt.loadNpmTasks('grunt-aws-lambda');
grunt.registerTask('ls-deploy', ['lambda_package:lambdaTest', 'lambda_deploy:lambdaTest']);
};
Step 6: Create awsCredentials.js
Create AWS IAM User with custom policy, Custom policy should have access to lambda:GetFunction
, lambda:UploadFunction
, lambda:UpdateFunctionCode
, lambda:UpdateFunctionConfiguration
and iam:PassRole
{
"accessKeyId": "XXXXXXXXXXXXXXXXXXXX",
"secretAccessKey": "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX"
}
Step 7: Create a zip and deploy to AWS Lambda.
ls-deploy
is custom task created by in Gruntfile above, which creates a zip of source code and deploy to Lambda.
grunt ls-deploy
Complete AWS Lambda Seed project is available on Git.
Its because in exports.handler, you are not referencing the index function. This can be solved in a more simpler way
Try this,
console.log('Loading function');
exports.handler = function index (event, context) {
console.log('value1 =', event.key1);
console.log('value2 =', event.key2);
console.log('value3 =', event.key3);
context.succeed(event.key1); // Echo back the first key value
// context.fail('Something went wrong');
}
The name of your file needs to match the module name in the Handler configuration. In this case, your Handler should be set to helloworld.handler
, where helloworld
is the file that would be require()'d and handler
is the exported function. Then it should work with the same zip file.
Make sure your index.js is in the root of the zipfile and not in a subdirectory.
In my case I had the name of the module matching the name of the file and the exported handler, the real problem was macOS and the zip program which basically creates a folder inside the zip file so when uncompressed in AWS Lambda engine the index.js ends in a subdirectory.
Don't right click and compress the directory, instead select the files individual files like index.js, package.json and the node_modules directory and right-click to compress, you may end up with a file Archive.zip in the same directory. The name of the zip file is not going to be fancy but at least it will work when you submit it to AWS Lambda.
You could make the same mistake using the command line with zip -r function.zip function
which basically creates a zip file with a directory called function
in it, instead do:
$ zip function.zip index.js package.json node_modules
adding: index.js (deflated 47%)
adding: package.json (deflated 36%)
adding: node_modules/ (stored 0%)
Using finder, if you double click the zip file and it uncompresses in a subdirectory then Lambda won't be able to see the file as index.js lives in that subdirectory.
Using the command line and zipinfo
:
$ zipinfo function.zip | grep index.js | more
-rw-r--rw- 2.1 unx 1428 bX defN 27-Jul-16 12:21 function/index.js
Notice how index.js ended up inside the subdirectory function
, you screwed up.
$ zipinfo function.zip | grep index.js | more
-rw-r--rw- 3.0 unx 1428 tx defN 27-Jul-16 12:21 index.js
Notice that index.js is not inside a subfolder, this zip file will work in AWS Lambda.
So I added a script to my package to zip the project files for me just by running npm run zip
{
"name": "function",
"version": "1.0.0",
"description": "",
"main": "index.js",
"scripts": {
"zip": "zip function.zip package.json *.js node_modules"
},
"dependencies": {
"aws-sdk": "^2.4.10"
}
}
$ npm run zip
> function@1.0.0 zip
> zip function.zip package.json *.js node_modules
adding: package.json (deflated 41%)
adding: index.js (deflated 47%)
adding: local.js (deflated 42%)
adding: node_modules/ (stored 0%)
Here is an advance way with AWS CLI. It will save your time in long term use.
First of all you should install and configure AWS CLI:
http://docs.aws.amazon.com/cli/latest/userguide/installing.html
1) Create an archive
$ zip -r lambda *
It will create for us lambda.zip file with all folders and files in the our current location.
2) Get role ARN
$ aws iam list-roles | grep "your_role"
It will return to us ARN that we will use with our lambda. You should create it by your hands
Example for list-roles
3) Create our lambda
$ aws lambda create-function --function-name "your_lambda_name" --zip-file fileb://lambda.zip --handler index.handler --runtime nodejs6.10 --timeout 15 --role COPY_HERE_YOUR_ARN_FROM_THE_STEP_2
We are done!