Rearrange dataframe to a table, the opposite of “melt” [duplicate]

Answer 1

Another approach with split:

mydfSplit <- split(mydf[,-2], mydf$class, drop=TRUE)

The result is a list which can be easily converted to a data.frame if the components have the same dimensions (which is true in this example):

mydf2 <- do.call(cbind, mydfSplit)

The problem with this solution is that the names of the final result need a cleaning. However, for a more general data, this can be useful if SN is different for each class.

Answer 2

In base R you could do it like this...

# get it sorted so that all you need to do is make a matrix out of it
mydf <- mydf[order(mydf$class, mydf$SN),]
# save the unique values of SN
SNu <- unique(mydf$SN)
# combine a matrix with SN
mydfw <- data.frame(SNu, matrix(mydf$myvar, nrow = length(SNu)))
# name your columns    
colnames(mydfw) <- c('SN', levels(mydf$class))

Or, for a more concise expression using aggregate

aggregate(myvar~SN, mydf, 'c')
# column names don't come out great
colnames(mydfw) <- c('SN', levels(mydf$class))

Answer 3

molten = melt( mydf , id.vars = c( "SN" , "class" ) , measure.vars = "myvar" )
casted = dcast( molten , SN~class )

Answer 4

> dcast(mydf, SN ~ class)

  SN         A1         B2          C3          D4
1  1  0.1461258  0.8325014  0.33562088 -0.07294576
2  2  0.5964182  0.4593710 -0.23652803 -1.52539568
3  3  2.0247742 -1.1235963  1.79875447 -1.87462227
4  4  0.8184004  1.3486721  0.76076486 -1.18311991
5  5 -0.6577212  0.3666741 -0.06057506  1.38825487
6  6  0.1590443  0.2043661  0.08161778  0.10421797
...