Generate a UUID on iOS from Swift

Question

In my iOS Swift app I want to generate random UUID (GUID) strings for use as a table key, and this snippet appears to work:

let uuid = CFUU         


        

Answer 1

You could also just use the NSUUID API:

let uuid = NSUUID()

If you want to get the string value back out, you can use uuid.UUIDString.

Note that NSUUID is available from iOS 6 and up.

Answer 2

Also you can use it lowercase under below

let uuid = NSUUID().UUIDString.lowercaseString
print(uuid)

Output

68b696d7-320b-4402-a412-d9cee10fc6a3

Thank you !

Answer 3

Try this one:

let uuid = NSUUID().uuidString
print(uuid)

Swift 3/4/5

let uuid = UUID().uuidString
print(uuid)

Answer 4

For Swift 3, many Foundation types have dropped the 'NS' prefix, so you'd access it by UUID().uuidString.

Answer 5

For Swift 4;

let uuid = NSUUID().uuidString.lowercased()

Answer 6

Each time the same will be generated:

if let uuid = UIDevice.current.identifierForVendor?.uuidString {
    print(uuid)
}

Each time a new one will be generated:

let uuid = UUID().uuidString
print(uuid)