How to assign string to bytes array

Question

I want to assign string to bytes array:

var arr [20]byte
str := \"abc\"
for k, v := range []byte(str) {
  arr[k] = byte(v)
}

Have another m

Answer 1

Go, convert a string to a bytes slice

You need a fast way to convert a []string to []byte type. To use in situations such as storing text data into a random access file or other type of data manipulation that requires the input data to be in []byte type.

package main

func main() {

    var s string

    //...

    b := []byte(s)

    //...
}

which is useful when using ioutil.WriteFile, which accepts a bytes slice as its data parameter:

WriteFile func(filename string, data []byte, perm os.FileMode) error

Another example

package main

import (
    "fmt"
    "strings"
)

func main() {

    stringSlice := []string{"hello", "world"}

    stringByte := strings.Join(stringSlice, " ")

    // Byte array value
    fmt.Println([]byte(stringByte))

    // Corresponding string value
    fmt.Println(string([]byte(stringByte)))
}

Output:

[104 101 108 108 111 32 119 111 114 108 100] hello world

Please check the link playground

Answer 2

Safe and simple:

[]byte("Here is a string....")

Answer 3

Arrays are values... slices are more like pointers. That is [n]type is not compatible with []type as they are fundamentally two different things. You can get a slice that points to an array by using arr[:] which returns a slice that has arr as it's backing storage.

One way to convert a slice of for example []byte to [20]byte is to actually allocate a [20]byte which you can do by using var [20]byte (as it's a value... no make needed) and then copy data into it:

buf := make([]byte, 10)
var arr [10]byte
copy(arr[:], buf)

Essentially what a lot of other answers get wrong is that []type is NOT an array.

[n]T and []T are completely different things!

When using reflect []T is not of kind Array but of kind Slice and [n]T is of kind Array.

You also can't use map[[]byte]T but you can use map[[n]byte]T.

This can sometimes be cumbersome because a lot of functions operate for example on []byte whereas some functions return [n]byte (most notably the hash functions in crypto/*). A sha256 hash for example is [32]byte and not []byte so when beginners try to write it to a file for example:

sum := sha256.Sum256(data)
w.Write(sum)

they will get an error. The correct way of is to use

w.Write(sum[:])

However, what is it that you want? Just accessing the string bytewise? You can easily convert a string to []byte using:

bytes := []byte(str)

but this isn't an array, it's a slice. Also, byte != rune. In case you want to operate on "characters" you need to use rune... not byte.

Answer 4

For example,

package main

import "fmt"

func main() {
    s := "abc"
    var a [20]byte
    copy(a[:], s)
    fmt.Println("s:", []byte(s), "a:", a)
}

Output:

s: [97 98 99] a: [97 98 99 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]

Answer 5

I think it's better..

package main

import "fmt"

func main() {
    str := "abc"
    mySlice := []byte(str)
    fmt.Printf("%v -> '%s'",mySlice,mySlice )
}

Check here: http://play.golang.org/p/vpnAWHZZk7

Answer 6

Besides the methods mentioned above, you can also do a trick as

s := "hello"
b := *(*[]byte)(unsafe.Pointer((*reflect.SliceHeader)(unsafe.Pointer(&s))))

Go Play: http://play.golang.org/p/xASsiSpQmC

You should never use this :-)