mysql_query() expects parameter 2 to be resource, string given in [duplicate]

Answer 1

try mysql_query("INSERT INTO ".$tbl_name."(city_id, city, state_id) VALUES(NULL,'".$city."','4421')") or die(mysql_error());

i guess it should work this way..

Answer 2

This is because of incorrect syntax and you column names in INSERT query should not be enclosed in quotes: try

$result = mysql_query("INSERT INTO ".$tbl_name."(city_id, city, state_id) VALUES(NULL, '".$city."','4421') or die(mysql_error()";

Answer 3

mysql_query("INSERT INTO $tbl_name(city_id, city, state_id) VALUES(NULL, ".$city.",'4421')") or die(mysql_error());

Try this.

or die() is a php construct - you misplaced a bracket which meant it went inside the sql query.

This is why your error thinks that mysql_query() has a second parameter.

Answer 4

You forgot to give closing " after after '4421'') and the syntax is incorrect!

Replace:

'NULL, '.$city.","', '4421'') or die(mysql_error())");

With

'NULL, '.$city.","', '4421'')") or die(mysql_error());

Answer 5

Your query shoul be like this

mysql_query("INSERT INTO $tbl_name(city_id, city, state_id) VALUES('NULL, '.$city.","', '4421'") or die(mysql_error()));

Columns without commas