I am making an android application that needs to search in my local area within 10km and display the results onto a map using pins, For example: \"Starbucks\", \"Wallmart\",
You can do this by using Google API JAVA Client - Here is an example using the java client for getting all the 60 results.
public PlacesList search(double latitude, double longitude, double radius, String types)
throws Exception {
try {
HttpRequestFactory httpRequestFactory = createRequestFactory(HTTP_TRANSPORT);
HttpRequest request = httpRequestFactory
.buildGetRequest(new GenericUrl("https://maps.googleapis.com/maps/api/place/search/json?"));
request.getUrl().put("key", YOUR_API_KEY);
request.getUrl().put("location", latitude + "," + longitude);
request.getUrl().put("radius", radius);
request.getUrl().put("sensor", "false");
request.getUrl().put("types", types);
PlacesList list = request.execute().parseAs(PlacesList.class);
if(list.next_page_token!=null || list.next_page_token!=""){
Thread.sleep(4000);
/*Since the token can be used after a short time it has been generated*/
request.getUrl().put("pagetoken",list.next_page_token);
PlacesList temp = request.execute().parseAs(PlacesList.class);
list.results.addAll(temp.results);
if(temp.next_page_token!=null||temp.next_page_token!=""){
Thread.sleep(4000);
request.getUrl().put("pagetoken",temp.next_page_token);
PlacesList tempList = request.execute().parseAs(PlacesList.class);
list.results.addAll(tempList.results);
}
}
return list;
} catch (HttpResponseException e) {
return null;
}
}
As far as the HTTP interface goes, your code LGTM assuming API_KEY
holds a valid API key. That is, one created in the API console. Try printing out the whole request.url
and see if it looks like this:
https://maps.googleapis.com/maps/api/place/search/json?key=AIzaSyDoTeTuPXXXXXXXXXMHPVYM5VTg&location=37.994682,-87.6045923&radius=500&sensor=false
Also see this thread because e.response
isn't valid, maybe just remove that call to println
and see what e
looks like when it's thrown.