Output of a C string program

Question

#include
int main()
{
  char s[2]=\"a\";
  s[1]=\'b\';s[2]=\'c\';s[3]=\'d\';s[5]=\'e\';
  printf(\"%s $%c$\",s,s[4]);
  return 0;
 }

Answer 1

1. It isn't necessary for a runtime error to occur. C does no bound checking.
2. There are many characters defined in C. Like the sound beep \a if I remebember correct so it isn't necessary that something is actually printed on the screen. It might have been a sound that you never heard.

Answer 2

Accessing out of bound of an array is undefined behaviour. Just an example same code's output on my system is abcd(e▒x $($

string of length 8 is because of lack of NULL terminator and character ( between $ is garbage value of s[4].

Answer 3

You are writing/reading outside of the bounds of the array, this is simply undefined behavior you can not make any predictions about what the program will do.