Integer.parse(String str) java.lang.NumberFormatException: Errors

Question

I keep getting number format expectations, even though I\'m trimming the strings and they don\'t contain non numerical characters bizarrely it works for some numbers and not

Answer 1

You could use

String n="3020857508";
Long a = Long.valueOf(n.trim()).longValue();
System.out.println(a);

Answer 2

Just like what @Codebender said. Your value is out of range for int. Try using long/Long instead.

Answer 3

MAX_INT is 2147483647 and you're trying to parse a bigger number as Integer.

You can use Long.parseLong instead:

System.out.println(Long.parseLong("3020857508")); // 3020857508

Answer 4

It's because 3020857508 exceeds Integer.MAX_VALUE. You should use long to convert the string to number.

java> String n="3020857508";
//=> java.lang.String n = "3020857508"
java> Integer a = Integer.parseInt(n.trim());
//=> java.lang.NumberFormatException: For input string: "3020857508"
java> Integer.MAX_VALUE
//=> java.lang.Integer res2 = 2147483647
java> Long a = Long.parseLong(n.trim());
//=>java.lang.Long a = 3020857508

The above is javarepl output.

If you are using JDK9 or above, you can see the same result in jshell.

jshell> String n="3020857508"
n ==> "3020857508"

jshell> Integer a = Integer.parseInt(n.trim())
|  Exception java.lang.NumberFormatException: For input string: "3020857508"
|        at NumberFormatException.forInputString (NumberFormatException.java:65)
|        at Integer.parseInt (Integer.java:652)
|        at Integer.parseInt (Integer.java:770)
|        at (#2:1)

jshell> Integer.MAX_VALUE
$3 ==> 2147483647

jshell> Long a = Long.parseLong(n.trim());
a ==> 3020857508

Answer 5

The largest number parseable as an int is 2147483647 (2³¹-1), and the largest long is 9223372036854775807 (2⁶³-1), only about twice as long.

To parse arbitrarily long numbers, use:

import java.math.BigInteger;

BigInteger number = new BigInteger(str);

Answer 6

The number you're trying to parse is larger than the max value of an Integer, you would have to use a larger data type like Long.

public static void main(String[] args) {
    System.out.println("Integer max value: " + Integer.MAX_VALUE);
    System.out.println("Long max value: " + Long.MAX_VALUE);
    System.out.println();

    String n = "3020857508";
    Long a = Long.parseLong(n.trim());
    System.out.println(a);
}

Results:

Integer max value: 2147483647
Long max value: 9223372036854775807

3020857508