How to deal with exceptions when using WebClient.DownloadFileAsync

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春和景丽
春和景丽 2020-12-11 17:53

I am downloading some files from the internet using a WebClient in the following way:

try  
{
   ManualResetEvent mr = new ManualResetEvent(fals         


        
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  • 2020-12-11 18:22

    You should use await and DownloadFileTaskAsync:

    try  
    {
    
       using (WebClient wc = new WebClient())
       {
    
             await  wc.DownloadFileTaskAsync(new Uri(string.Format("{0}/{1}", Settings1.Default.WebPhotosLocation, Path.GetFileName(f.FullName))), filePath);
    
        }
    }
    catch (Exception ex)
    {
       //Catch my error here and handle it (display message box)
    }
    

    DownloadFileAsync uses Event-based Asynchronous Pattern, you can't catch the exception, you can get exception throw AsyncCompletedEventArgs.Error Property

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  • 2020-12-11 18:29

    Bad solution with rethrowing

    You can save the exception in some variable defined outside the lambda. Then it can be rethrown:

    Exception exc = null;
    using (WebClient wc = new WebClient())
    {
          wc.DownloadFileCompleted += ((sender, args) =>
          ...
    
          mr.WaitOne();
    
          if (exception != null) throw exception;
    }
    

    Why is it bad? Because you will loose the stacktrace(it will show that the exception was thrown in the current method, not in the WebClient). Still, if you do not need or do not care about stacktrace, it is possible solution.

    Handling the exception in place

    You can also just create some method that will handle the exception in both the outer try-catch and in the downloaded handler:

    void HandleWebClientException(Exception exc)
    {
        ...
    }
    
    try  
    {
       ManualResetEvent mr = new ManualResetEvent(false);
       mr.Reset();
       using (WebClient wc = new WebClient())
       {
              wc.DownloadFileCompleted += ((sender, args) =>
              {
                   if (args.Error == null)
                   {
                        File.Move(filePath, Path.ChangeExtension(filePath, ".jpg"));
                        mr.Set();
                   }
                   else
                   {
                      HandleWebClientException(args.Error);
                   }
               });
               wc.DownloadFileAsync(new Uri(string.Format("{0}/{1}", Settings1.Default.WebPhotosLocation, Path.GetFileName(f.FullName))), filePath);
               mr.WaitOne();
        }
    }
    catch (Exception ex)
    {
       HandleWebClientException(ex);
    }
    

    Doing it right

    The best idea is to avoid void methods on WebClient, because you can't await on them or apply some continuation.

    Such methods are convenient in some sense, but they force you to use clandestine solutions with synchronization constructs to make the workflow less dependent on different callbacks.

    To use async-await you will have to apply public Task<byte[]> DownloadDataTaskAsync(Uri address) method.

    You can either:

    1. await it to get the byte array of data to save it later manually, but it will require a solid rework in your application to make it async all the way:

    public async Task LoadFile()
    {
        try
        {
            using (WebClient wc = new WebClient())
            {
                var bytes = await wc.DownloadDataTaskAsync(new Uri(string.Format("{0}/{1}", Settings1.Default.WebPhotosLocation, Path.GetFileName(f.FullName))), filePath);
                System.IO.File.WriteAllBytes(bytes); // Probably turn it into async too
            }                    
        }
        catch (Exception ex)
        {
            //Catch my error here and handle it (display message box)
        }
    }
    

    It will work, but I am not sure that DownloadDataTaskAsync is a true async method.

    2. So you may also consider using Task Continuations with the same method:

    public Task LoadFile()
    {
        Task<Byte[]> bytesTask = wc.DownloadDataTaskAsync(new Uri(string.Format("{0}/{1}", Settings1.Default.WebPhotosLocation, Path.GetFileName(f.FullName))), filePath);
    
        var success = bytesTask.ContinueWith((prev) =>
            {
                System.IO.File.WriteAllBytes(prev.Result); 
            },
            TaskContinuationOptions.OnlyOnRanToCompletion);
    
    
        var failure = bytesTask.ContinueWith(prev =>
            {
                MessageBox.Show //...
            },
            TaskContinuationOptions.OnlyOnFaulted);
    
        return Task.WhenAny(success, failure);
    }
    

    P.S.: And why don't you just use the simple blocking method public void DownloadFile(Uri address, string fileName) if you have no need to load files asynchronously?

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  • 2020-12-11 18:29

    What you can do is create a Task (an async operation) and use the ContinueWith directive to handle the exception. This can be a bit unreadable

    using (WebClient wc = new WebClient())
    {
        wc.DownloadFileCompleted += ((sender, args) =>
        {
            if (args.Error == null)
            {
                File.Move(filePath, Path.ChangeExtension(filePath, ".jpg"));
                mr.Set();
            }
            else
            {
                //how to pass args.Error?
            }
        });
        Task.Factory.StartNew(() => wc.DownloadFile(
                                     new Uri(string.Format("{0}/{1}",
                                     Settings1.Default.WebPhotosLocation,
                                     Path.GetFileName(f.FullName))), filePath))
                    .ContinueWith(t => Console.WriteLine(t.Exception.Message));
    }
    

    However, with the introduction of .NET 4.5, Webclient exposes a task based async download for you!

    using (WebClient wc = new WebClient())
    {
        wc.DownloadFileCompleted += ((sender, args) =>
        {
            if (args.Error == null)
            {
                File.Move(filePath, Path.ChangeExtension(filePath, ".jpg"));
                mr.Set();
            }
            else
            {
                //how to pass args.Error?
            }
        });
        wc.DownloadFileTaskAsync(new Uri(string.Format("{0}/{1}",
                                     Settings1.Default.WebPhotosLocation,
                                     Path.GetFileName(f.FullName))),
                                     filePath)
          .ContinueWith(t => t.Exception.Message)
    }
    
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