I have a variable with the following value
$month = 201002;
the first 4 numbers represent the year, and the last 2 numbers represent the m
This may help you..
$month = substr($month, -2, 2);
echo date('M', strtotime(date('Y-'. $month .'-d')));
Append "01" and strtotime will be able to parse the string :
echo date('M', strtotime($month . '01'));
The second parameter of date is a timestamp. Use mktime to create one.
$month = 201002;
$monthNr = substr($month, -2, 2);
$timestamp = mktime(0, 0, 0, $monthNr, 1);
$monthName = date('M', $timestamp );
$mydate = "201002";
date('M', mktime(0, 0, 0, substr($mydate, 4, 2), 1, 2000));
You can use the DateTime Class to get a Date data structure using date string and format. Then get a date string with any format like this:
$month = 201002;
$date = DateTime::createFromFormat('Yd', $month);
$monthName = $date->format('M'); // will get Month name
Being a programmer, and even knowing nothing of PHP data magic, I'd made it
$month = intval(substr($input_date,4,2));
$mons = explode(" ","Zer Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec");
echo $mons[$month];