PHP:find day difference between two date(“YmdHis”) reture

Question

I need to find the day difference from the date(\"YmdHis\") value.let say one value is:

$previous_date=\'20101202115755\';
$current_date= date(\         


        

Answer 1

You have a strange format...

1. Parse it to get a UNIX timestamp with strptime and mktime:

   $d = strptime($previous_date, '%Y%m%d%H%M%S');
   $prev_ts = mktime($d['tm_hour'], $d['tm_min'], $d['tm_sec'], $d['tm_mon'] + 1, $d['tm_mday'], $d['tm_year'] + 1900);
   

2. Subtract the timestampes (time() gives the current time):

   $diff = time() - $prev_ts;
   

3. Divide by 60*60*24 seconds to get the difference in days:

   $diff = floor($diff / (60*60*24)); // or round(), ceil() whatever fits best
   

That said, if possible try to store or get the date not as 20101202115755 but as UNIX timestamp. Then you don't have to go through the conversion hassle.

Working DEMO

Answer 2

For PHP >= 5.3.0:

$prev = DateTime::createFromFormat("YmdHis", '20101202115755');
$curr = new DateTime();
$diff = $curr->diff($prev);
echo "Difference: ".$diff->days;

Answer 3

Just convert your dates to timestamps and then subtract previous_date from current_date and divide by number of seconds in a day. This is an example:

$day = 60*60*24;

$now = time();
$target = strtotime('2010-12-24');

$diff = round(($target - $now) / $day);
echo $diff;

If you want number of days in between, subtract $diff by one.

Answer 4

<?php
$previous_date="201012021157552";
$previous_date_as_time = mktime(
  substr($previous_date, 8, 2),
  substr($previous_date, 10, 2),
  substr($previous_date, 12, 2),
  substr($previous_date, 4, 2),
  substr($previous_date, 6, 2),
  substr($previous_date, 0, 4)
);

$days_between_dates = (time() - $previous_date_as_time) / 86400;

echo $days_between_dates;
?>