Convert Soap XML response to Object

Question

i\'m new to working with SOAP API\'s

I have a soap response from an API

Answer 1

IMO, you should consider using tools to handle SOAP messages instead of doing it on your own.

Examples :

• Java EE 5 Tutorial : Creating a Simple Web Service and Client with JAX-WS
• Spring Boot : Consuming a SOAP message

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EDIT

There's a few things to say about your comment so I'll put my answer here.

First,

I have nothing to do with the API, all I do is make a POST request...

You have nothing to do with the API but you make a POST request to the API. I think this is a figure of speech, right ?...

and there's no wsdl....

You can almost always get the WSDL of a SOAP webservice with this little trick. Just add ?wsdl at the end of the SOAP webservice URL.

Example :

Here's the URL of a SOAP webservice on the web (a real one) : http://www.webservicex.com/stockquote.asmx

You can get its WSDL like this : http://www.webservicex.com/stockquote.asmx?wsdl

So the only option is to parse the response

IMO, there's almost always more than one solution to a problem in software development.

Answer 2

you can use this code to retrieve a POJO, and also add an @XmlRootElement as header to your POJO.

(I did'nt test the code below)

XMLInputFactory xif = XMLInputFactory.newFactory();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
        xsr.nextTag(); // Advance to Envelope tag

        xsr.nextTag(); // Advance to Body tag
        xsr.nextTag();
        xsr.nextTag();

        Transformer transformer = TransformerFactory.newInstance().newTransformer();
        StringWriter stringWriter = new StringWriter();
        transformer.transform(new StAXSource(xsr), new StreamResult(stringWriter));
        StringReader sr = new StringReader(stringWriter.toString());
        JAXBContext jaxbContext = JAXBContext.newInstance(LoginResult.class);
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
        LoginResult loginResult = (LoginResult) unmarshaller.unmarshal(sr);

EDIT :

I found a solution for you:

    @XmlRootElement(name = "LoginResult", namespace = "http://test.org/ADMail_Service")
@XmlAccessorType(XmlAccessType.FIELD)
public class LoginResult {
    @XmlElement(name = "ErrorMessage", namespace = "http://test.org/ADMail_Service")
    private String errorMessage;
    @XmlElement(name = "Status", namespace = "http://test.org/ADMail_Service")
    private String status;

    public String getErrorMessage() {
        return errorMessage;
    }

    public void setErrorMessage(String errorMessage) {
        this.errorMessage = errorMessage;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }
}


public static void main(String[] args) {
        try {
            XMLInputFactory xif = XMLInputFactory.newFactory();
            XMLStreamReader xsr = xif.createXMLStreamReader(new FileReader("input.xml"));
            xsr.nextTag(); // Advance to Envelope tag

            xsr.nextTag(); // Advance to Body tag
            xsr.nextTag();
            xsr.nextTag();


            JAXBContext jc = JAXBContext.newInstance(LoginResult.class);
            Unmarshaller unmarshaller = jc.createUnmarshaller();
            JAXBElement<LoginResult> je = unmarshaller.unmarshal(xsr, LoginResult.class);

            System.out.println(je.getName());
            System.out.println(je.getValue());
            System.out.println(je.getValue().getErrorMessage());
        } catch (XMLStreamException e) {
            e.printStackTrace();
        } catch (JAXBException e) {
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        }

    }