Perl regular expression to match an IP address

Question

I have written this code, but it does not work. Can someone point out the issue?

sub match_ip()
{
  my $ip = \"The IP address is 216.108.225.236:60099\";
  i         


        

Answer 1

Alternatively, you can use Data::Validate::IP, with the caveat that it won't recognize the port, so you'll have to split on :.

use strict;
use warnings;
use Data::Validate::IP;

my $ip_with_port="216.108.225.236:60099";
my $ip=(split /:/,$ip_with_port)[0];

my $validator=Data::Validate::IP->new;

if($validator->is_ipv4($ip))
{
  print "Yep, $ip is a valid IPv4 address.\n";
}
else
{
  print "Nope, $ip is not a valid IPv4 address.\n";
}

The output is:

Yep, 216.108.225.236 is a valid IPv4 address.

Answer 2

In the spirit of TIMTOWTDI here is another: the Regexp::Common::net portion of Regexp::Common may have regexen that you desire.

Answer 3

#!/usr/bin/perl

$str = 'IP address is : 70.21.311.105';

    if ($str =~ m/(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})/) {
        if ($1 <= 255 && $2 <= 255 && $3 <= 255 && $4 <= 255 ) {
            print "Valid $str\n";
    } else {
          print "invalid IP $str\n";
    }
}


__END__

Answer 4

use strict;
use warnings;
open(FH,"<fileName.txt") or die "file not found ,$_";
while(my $line=<FH>)
{
push(my @arr,($line));
foreach my $arrVal (@arr)
{           
if($arrVal=~/IPv4 Address(?=.*\b((25[0-5]|2[0-4]\d|[0-1]?\d?\d)(\.(25[0-5]|2  [0-4]\d|[0-1]?\d?\d)){3})\b)/)
{
print "$arrVal\n";
}
}

Answer 5

Try this:

$variablename=~m/((((0-9)|((1-9)(0-9))|(1([0-9]){2})|(2[0-4][0-9])|(2[5][0-5]))\.){3})((0-9)|((1-9)(0-9))|(1([0-9]){2})|(2[0-4][0-9])|(25[0-5]))/)