Python: List of lists to dictionary [closed]

Answer 1

I'm going to play guess-what-you-want, and assume the first numbers in each row are in fact some kind of sequential identifier, and you want

1    30    5
2    64    4

to become

1  : [30, 5]
2  : [64, 4]

so...

with open("dataFile.txt") as dataFile:
    items = {}
    for line in dataFile:
        line = map(int, line.split())  #convert the text data to integers
        key, value = line[0], line[1:]
        items[key] = value

(and I've changed the name of file because file() is already a builtin function in Python, and reusing that name for something else is bad form).

---

Or you could use a dictionary comprehension instead, starting with your items list:

itemDict = {item[0]: item[1:] for item in items}

Answer 2

Assuming you want your dictionary key to be the 1st element of the list, here is an implementation:

list = [[1, 30, 5], [2, 64, 4]]
dict = {}

for l2 in list:
    dict[l2[0]] = l2[1:]

It works by iterating through list, and the sub-list l2. Then, I take the 1st element of l2 and assign it as a key to dict, and then take the rest of the elements of l2 and put it as the value.

The result is the finished dictionary {1: [30, 5], 2: [64, 4]}