how to find first and last record from mysql table

Question

I have one table I want to find first and last record that satisfy criteria of particular month.

Answer 1

First and last make sense only when you have the output of the query sorted on a field(s).

To get the first record:

select col1 from tab1 order by col1 asc limit 1;

To get the last record:

select col1 from tab1 order by col1 desc  limit 1;

Answer 2

select * from table
where id = (select id from tab1 order by col1 asc limit 1) or
id = (select id from tab1 order by col1 desc  limit 1);

Answer 3

How about something like:

select 'first', f1, f2, f3, f4 from tbl
    order by f1 asc, f2 asc
    limit 1
union all
select 'last', f1, f2, f3, f4 from tbl
    order by f1 desc, f2 desc
    limit 1

Obviously feel free to add whatever condition you want in a where clause but the basic premise of the order by is to reverse the order in the two select sections.

The limit clause will just get the first row in both cases. That just happens to be the last row of set in the second select due to the fact that you've reversed the ordering.

If there is only one row resulting from your conditions and you don't want it returned twice, use union instead of union all.

Answer 4

SELECT 
(SELECT column FROM table WHERE [condition] ORDER BY column LIMIT 1) as 'first',
(SELECT column FROM table WHERE [condition] ORDER BY column DESC LIMIT 1) as 'last'

This worked for me when I needed to select first and the last date in the event series.

Answer 5

SELECT * FROM (
    SELECT first_name, LENGTH(first_name) FROM Employees
    ORDER BY LENGTH(first_name) ASC
    FETCH FIRST 1 rows ONLY)
UNION
SELECT * FROM (
    SELECT first_name, LENGTH(first_name) FROM Employees
    ORDER BY LENGTH(first_name) DESC
    FETCH FIRST 1 rows ONLY)
ORDER BY 2 desc;