sort array with integer strings type in jQuery

Question

I have a array of integers of type string.

var a = [\'200\',\'1\',\'40\',\'0\',\'3\'];

output

>>> var a = [\'2         


        

Answer 1

You need to write your own sort function.

a.sort(function(a,b)) {
    var intValA = parseInt(a, 10);
    var intValB = parseInt(b, 10);

    if (!isNaN(parseInt(a, 10))) && !isNaN(parseInt(b, 10)) {
        // we have two integers
        if (intValA > intValB)
            return 1;
        else if (intValA < intValB)
            return 0;
        return 1;
    }
    if (!isNaN(parseInt(a, 10)) && isNaN(parseInt(b, 10)))
        return 1;
    if (isNaN(parseInt(a, 10)) && !isNaN(parseInt(b, 10)))
        return -1;

    // a and b are not integers
    if (a > b)
        return 1;
    if (a < b)
        return -1;
    return 0;
});

Answer 2

As others said, you can write your own comparison function:

var arr = ["200", "1", "40", "cat", "apple"]
arr.sort(function(a,b) {
  if (isNaN(a) || isNaN(b)) {
    return a > b ? 1 : -1;
  }
  return a - b;
});

// ["1", "40", "200", "apple", "cat"]

Answer 3

Most javascript implementations, as far as I know, provide a function you can pass in to provide your own custom sorting.

Mozilla sort Method

Answer 4

Thanks all, though I dont know jQuery much, but from you guys examples, I summarized the code as follows which works as per my requirement

to be used in firebug

var data = ['10','2', 'apple', 'c' ,'1', '200', 'a'], temp;
temp = data.sort(function(a,b) {
         var an = +a;
         var bn = +b;
          
         if (!isNaN(an) && !isNaN(bn)) {
             return an - bn;
         } 
         return a<b ? -1 : a>b ? 1 : 0;
     }) ;
alert(temp);

Answer 5

This should be what you're looking for

var c = ['200','1','40','cba','abc'];
c.sort(function(a, b) {
  if (isNaN(a) || isNaN(b)) {
    if (a > b) return 1;
    else return -1;
  }
  return a - b;
});
// ["1", "40", "200", "abc", "cba"]