Parse JSON array as std::string with Boost ptree

Question

I have this code that I need to parse/or get the JSON array as std::string to be used in the app.

std::string ss = \"{ \\\"id\\\" : \\\"123\\\", \\\"number\         


        

Answer 1

Arrays are represented as child nodes with many "" keys:

docs

• JSON arrays are mapped to nodes. Each element is a child node with an empty name. If a node has both named and unnamed child nodes, it cannot be mapped to a JSON representation.

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#include <boost/property_tree/ptree.hpp>
#include <boost/property_tree/json_parser.hpp>

using boost::property_tree::ptree;

int main() {
    std::string ss = "{ \"id\" : \"123\", \"number\" : \"456\", \"stuff\" : [{ \"name\" : \"test\" }, { \"name\" : \"some\" }, { \"name\" : \"stuffs\" }] }";

    ptree pt;
    std::istringstream is(ss);
    read_json(is, pt);

    std::cout << "id:     " << pt.get<std::string>("id") << "\n";
    std::cout << "number: " << pt.get<std::string>("number") << "\n";
    for (auto& e : pt.get_child("stuff")) {
        std::cout << "stuff name: " << e.second.get<std::string>("name") << "\n";
    }
}

Prints

id:     123
number: 456
stuff name: test
stuff name: some
stuff name: stuffs

Answer 2

continue with @sehe 's answer, related to the question asked by @xkm

Is it possible to get it like '[{ "name" : "some" }, { "name" : "stuffs" }]'

Yes, you can. Just treat it with an "unnamed" key which means the key with empty string.

f.g.

#include <boost/property_tree/ptree.hpp>
#include <boost/property_tree/json_parser.hpp>

#include <iostream>

using boost::property_tree::ptree;

int main()
{
    std::stringstream ss;
    ss << R"([{"a": 5}, {"a": 9}])";

    ptree pt;
    read_json(ss, pt);
    for (auto& item : pt.get_child(""))
       std::cout << "value is " << item.second.get<int>("a") << std::endl;
}

Answer 3

Since "stuff" is an array, you can iterate over the elements of it, which are dictionaries. And then you can iterate over the elements of the dictionary, which are key-value pairs:

for (const auto& dict : pt2.get_child("stuff")) {
    for (const auto& kv : dict.second) {
        std::cout << "key = " << kv.first << std::endl;
        std::cout << "val = " << kv.second.get_value<std::string>() << std::endl;
    }
}