Python SimpleHTTPServer

Question

Is there a way to make Python SimpleHTTPServer supports mod_rewrite?

I\'m trying things with Ember.js with leveraging History API as the location API, and to make it

Answer 1

No mod_rewrite in Python servers I am afraid, unless you run python scripts behind an Apache server, a resource-costly solution.

Try Cherrypy (http://www.cherrypy.org/), which allows you to manage your page handlers, and very simply makes clean URLs.

Answer 2

If you know the cases you need to redirect you can subclass SimpleHTTPRequestHandler and do a redirect. This redirects any missing file requests to /index.html

import SimpleHTTPServer, SocketServer
import urlparse, os

PORT = 3000

class MyHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
   def do_GET(self):

       # Parse query data to find out what was requested
       parsedParams = urlparse.urlparse(self.path)

       # See if the file requested exists
       if os.access('.' + os.sep + parsedParams.path, os.R_OK):
          # File exists, serve it up
          SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self);
       else:
          # redirect to index.html
          self.send_response(302)
          self.send_header('Content-Type', 'text/html')  
          self.send_header('location', '/index.html')  
          self.end_headers()

Handler = MyHandler

httpd = SocketServer.TCPServer(("", PORT), Handler)

print "serving at port", PORT
httpd.serve_forever()

Answer 3

SimpleHTTPServer does not support apache modules and does not respect .htaccess, because it isn't apache. it won't work with php either.

Answer 4

By modifying pd40's answer, I came up with this which doesn't redirect, it does your traditional "send index.html instead of 404". Not at all optimized, but it works for testing and development which is all I needed.

import SimpleHTTPServer, SocketServer
import urlparse, os

PORT = 3456

class MyHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
   def do_GET(self):

       # Parse query data to find out what was requested
       parsedParams = urlparse.urlparse(self.path)

       # See if the file requested exists
       if os.access('.' + os.sep + parsedParams.path, os.R_OK):
          # File exists, serve it up
          SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self);
       else:
          # send index.hmtl
          self.send_response(200)
          self.send_header('Content-Type', 'text/html')
          self.end_headers()
          with open('index.html', 'r') as fin:
            self.copyfile(fin, self.wfile)

Handler = MyHandler

httpd = SocketServer.TCPServer(("", PORT), Handler)

print "serving at port", PORT
httpd.serve_forever()