Python Lists - Finding Number of Times a String Occurs

Question

How would I find how many times each string appears in my list?

Say I have the word:

\"General Store\"

that is in my list like 20 t

Answer 1

You can use a dictionary, you might want to consider just using a dictionary from the beginning instead of a list but here is a simple setup.

#list
mylist = ['General Store','Mall','Ice Cream Van','General Store']

#takes values from list and create a dictionary with the list value as a key and
#the number of times it is repeated as their values
def votes(mylist):
d = dict()
for value in mylist:
    if value not in d:
        d[value] = 1
    else:
        d[value] +=1

return d

#prints the keys and their vaules
def print_votes(dic):
    for c in dic:
        print c +' - voted', dic[c], 'times'

#function call
print_votes(votes(mylist))

It outputs:

Mall - voted 1 times
Ice Cream Van - voted 1 times
General Store - voted 2 times

Answer 2

Use the count method. For example:

(x, mylist.count(x)) for x in set(mylist)

Answer 3

votes=["General Store", "Mall", "General Store","Ice Cream Van","General Store","Ice Cream Van","Ice Cream Van","General Store","Ice Cream Van"]

for vote in set(votes):
    print(vote+" - voted "+str(votes.count(vote))+" times")

Try this. It will output

General Store - voted 4 times
Ice Cream Van - voted 4 times
Mall - voted 1 times

Answer 4

I like one-line solutions to problems like this:

def tally_votes(l):
  return map(lambda x: (x, len(filter(lambda y: y==x, l))), set(l))

Answer 5

just a simple example:

   >>> lis=["General Store","General Store","General Store","Mall","Mall","Mall","Mall","Mall","Mall","Ice Cream Van","Ice Cream Van"]
   >>> for x in set(lis):
        print "{0}\n{1}".format(x,lis.count(x))


    Mall
    6
    Ice Cream Van
    2
    General Store
    3

Answer 6

First use set() to get all unique elements of the list. Then loop over the set to count elements from the list

unique = set(votes)
for item in unique:
    print item
    print votes.count(item)