Calculate the last day of the prior quarter

Question

What\'s the most efficient way to calculate the last day of the prior quarter?

Example: given the date 11/19/2008, I want to return 9/30/2008.

Platform is S

Answer 1

In amazon redshift:

Last day of the previous quarter:

select dateadd(day,-1,DATE_TRUNC('qtr', current_date)) from whatever

Last day of current quarter:

select dateadd(qtr,1,dateadd(day,-1,DATE_TRUNC('qtr', current_date))) from whatever

Answer 2

Get the current date

SELECT CONVERT(DATE,GETDATE()) [Current Date]

Get the 1st date of the quarter for the current date

SELECT CONVERT(DATE, DATEADD(QQ, DATEDIFF(QQ, 0, GETDATE())  ,0)) [Current Quarter 1st Date]

Get the last date of the quarter for the current date

SELECT CONVERT(DATE,DATEADD(d, -1, DATEADD(q, DATEDIFF(q, 0, GETDATE()) +1, 0))) [Current Quarter Last Date]

Get the 1st date of the next quarter for the current date

SELECT CONVERT(DATE, DATEADD(QQ, DATEDIFF(QQ, 0, GETDATE()) +1 ,0)) [Next Quarter 1st Date]

Get the last date of the next quarter for the current date

SELECT CONVERT(DATE,DATEADD(d, -1, DATEADD(q, DATEDIFF(q, 0, GETDATE()) +2, 0))) [Next Quarter Last Date]

Answer 3

I came up with this (tested for all months):

select dateadd(dd,-1,dateadd(qq,datediff(qq,0,'11/19/2008'),0)),
       dateadd(dd,-1,dateadd(qq,datediff(qq,0,'10/19/2008'),0)),
       dateadd(dd,-1,dateadd(qq,datediff(qq,0,'12/19/2008'),0))

It might turn out to be the simplest.

Answer 4

If @Date has the date in question

Select DateAdd(day, -1, dateadd(qq, DateDiff(qq, 0, @Date), 0)) 

EDIT: Thanks to @strEagle below, simpler still is:

Select dateadd(qq, DateDiff(qq, 0, @Date), -1) 

Answer 5

convert(varchar, dateadd(dd,-1,dateadd(qq,1,DATEADD(qq, DATEDIFF(qq,0,YOUR_DATE), 0))),112)

you also can change 112 base on this below list

SELECT convert(varchar, getdate(), 100) -- mon dd yyyy hh:mmAM (or PM)
                                        -- Oct  2 2008 11:01AM
SELECT convert(varchar, getdate(), 101) -- mm/dd/yyyy - 10/02/2008                  
SELECT convert(varchar, getdate(), 102) -- yyyy.mm.dd – 2008.10.02           
SELECT convert(varchar, getdate(), 103) -- dd/mm/yyyy
SELECT convert(varchar, getdate(), 104) -- dd.mm.yyyy
SELECT convert(varchar, getdate(), 105) -- dd-mm-yyyy
SELECT convert(varchar, getdate(), 106) -- dd mon yyyy
SELECT convert(varchar, getdate(), 107) -- mon dd, yyyy
SELECT convert(varchar, getdate(), 108) --  hh:mm:ss
SELECT convert(varchar, getdate(), 109) -- mon dd yyyy hh:mm:ss:mmmAM (or PM)
                                        -- Oct  2 2008 11:02:44:013AM   
SELECT convert(varchar, getdate(), 110) -- mm-dd-yyyy
SELECT convert(varchar, getdate(), 111) -- yyyy/mm/dd
SELECT convert(varchar, getdate(), 112) -- yyyymmdd
SELECT convert(varchar, getdate(), 113) -- dd mon yyyy hh:mm:ss:mmm
                                        --  02 Oct 2008 11:02:07:577     
SELECT convert(varchar, getdate(), 114) -- hh:mm:ss:mmm(24h)
SELECT convert(varchar, getdate(), 120) -- yyyy-mm-dd hh:mm:ss(24h)
SELECT convert(varchar, getdate(), 121) --  yyyy-mm-dd hh:mm:ss.mmm
SELECT convert(varchar, getdate(), 126) -- yyyy-mm-ddThh:mm:ss.mmm
                                        --  2008-10-02T10:52:47.513
-- SQL create different date styles with t-sql string functions
SELECT replace(convert(varchar, getdate(), 111), '/', ' ') -- yyyy mm dd
SELECT convert(varchar(7), getdate(), 126)                 -- yyyy-mm
SELECT right(convert(varchar, getdate(), 106), 8)          -- mon yyyy

Answer 6

Actually simpler is:

SELECT DATEADD(qq, DATEDIFF(qq, 0, GETDATE()), -1)