How can I find the width of an image using PHP?

Question

I was wondering how can I find the width of an image using php.

Answer 1

As of PHP 7.1 you can do:

[0 => $width, 1 => $height, 'mime' => $mime] = getimagesize($filename);

This eliminates the need to turn $type into mime-type, while retaining the elegant array style list() assignments.

Answer 2

You can try with this code, you can see more in www.php.net

To a file:

<?php
list($width, $height, $type, $attr) = getimagesize("img/flag.jpg");
echo "<img src=\"img/flag.jpg\" $attr alt=\"getimagesize() example\" />";
?>

To URL:

<?php
$size = getimagesize("http://www.example.com/gifs/logo.gif");
$size = getimagesize("http://www.example.com/gifs/lo%20go.gif");

?>

Only you have to give an output to variable.

Answer 3

Check here for official document

list($Img_width, $Img_height) = getimagesize('Image Path');
echo "Width: " . $Img_width. "<br />";
echo "Height: " .  $Img_height;

Answer 4

Use the GD libraries imagesx function, take a look at the manual page here.

Answer 5

Easy, you can use getimagesize:

list($width, $height) = getimagesize($filename);

Answer 6

getimagesize()