In MySQL, how to return the week of the month?

Question

The year is divided into 12 months. We can break down a month in four weeks.

In MySQL, how to return the week of the month? (Example: first week: 2 entries, second w

Answer 1

Week of month (where the starting incomplete week is counted as a whole)

select ceiling((day(now()) - 
(6 - weekday(date_format(now(),'%Y-%m-01'))))/7) 
+ case when 6 - weekday(date_format(now(),'%Y-%m-01'))> 0 
then 1 else 0 end week_of_month;

Answer 2

SELECT (WEEK('2020-09-27') - WEEK(DATE_FORMAT('2020-09-27','%Y-%m-01')))+1

Answer 3

SELECT WEEK(my_date_field,5) - WEEK(DATE_SUB(my_date_field, 
INTERVAL DAYOFMONTH(my_date_field) - 1 DAY),5) + 1

Or you can see here.

Answer 4

FLOOR((DayOfMonth(dateCol)-1)/7)+1

I'd like to make it clear that this is probably not a good way to divide your data - (see the comments), but that this will get you as close as you can get.

Answer 5

Use the MySQL built-in function week to find the week number for the year, then subtract the week number for the first day of the month.

SELECT WEEK('2012-02-20') - WEEK('2012-02-01')

there are plenty of options in the documentation to customize the call to fit exactly what you are looking for, but I hope my example gives you an idea of what is available to you.

http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_week

Answer 6

TO_CHAR(my_date, 'W') 

Returns exact number of week in particular month.