Let us say we have a function.
function Rabbit(){
console.log(\"shiv\");
}
Now without creating an object of this function i can assign
what does this mean. do this add a variable bark to function. or do this added a property to Rabbit object
do this add a variable bark to function - No
or do this added a property to Rabbit object - Yes
bark is a property of object of type Function
even if i am not creating an object using new operator
Rabit is already an object (of type Function). You are not creating an instance of this object, just that you are adding a property to it.
Function in JavaScript is just an object, it is called Function object.
And just like any other types of object, it has its own constructor (new Function(...)
), methods (apply
, bind
, call
...) and properties (arguments
, caller
, name
...) . See the document.
You might be familiar with creating a function like this:
function Rabbit() {
console.log('shiv');
}
Then you should know that you can also create a function like this:
var Rabbit = new Function('console.log("shiv")');
Now, you might guess it out. If you add a new property to a Function object, as long as you don't overwrite the existing one, the function is still working just fine.
do this add a variable bark to function
this
object using Rabbit.bind(object)
do this added a property to Rabbit object